如何将操作转换为具有相同签名的已定义委托?

How to convert an action to a defined delegate of the same signature?(如何将操作转换为具有相同签名的已定义委托?)

本文介绍了如何将操作转换为具有相同签名的已定义委托?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

class Test
{
    public delegate void FruitDelegate(Fruit f);

    public void Notify<T>(Action<T> del) where T : Fruit
    {
        FruitDelegate f = del; // Cannot implicitly convert type 'Action<T>' to 'FruitDelegate
    }
}

Fruit 是一个空类.这两个代表都有相同的签名.

Fruit is an empty class. Both of these delegates have the same signature.

我似乎无法让这些工作.如果我解释一下我正在尝试做什么(提供一些上下文),也许会有所帮助.

I cannot seem to get any of this working. Maybe it would help if I explained what I am trying to do (provide some context).

我想创建一个具有通用静态方法的类,该方法提供类型和方法回调(如上例).

I want to create a class that has a generic static method that provides a type and a method callback (like the above example).

我遇到的问题是委托包含一个参数,我不想在方法回调中强制转换它.例如,我想要这个:

The problem I am having is that the delegate contains a parameter and I don't want to have to cast it within the method callback. For example, I want this:

public void SomeMethod()
{
    Test.Notify<Apple>(AppleHandler);
}

private void AppleHandler(Apple apple)
{

}

而不是这个:

public void SomeMethod()
{
    Test.Notify<Apple>(AppleHandler);
}

private void AppleHandler(Fruit fruit)
{
    Apple apple = (Apple)fruit;
}

这种事情可能吗?

推荐答案

这是你想要的吗?

static void Main(string[] args)
{

    Program p = new Program();
    p.SomeMethod();
}

public class Fruit
{ }

public class Apple : Fruit { }

public delegate void FruitDelegate<in T>(T f) where T : Fruit;

class Test
{
    public static void Notify<T>(FruitDelegate<T> del)
        where T : Fruit, new()
    {
        T t = new T();
        del.DynamicInvoke(t);
    }
}

private void AppleHandler(Apple apple)
{
    Console.WriteLine(apple.GetType().FullName);
}

public void SomeMethod()
{
    FruitDelegate<Apple> del = new FruitDelegate<Apple>(AppleHandler);
    Test.Notify<Apple>(del);
}

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本文标题为:如何将操作转换为具有相同签名的已定义委托?

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