Getting the next item from a Java 8 stream(从 Java 8 流中获取下一项)
问题描述
我想从 Java 8 Stream
中检索并删除下一个项目,而此 Stream
不会关闭.
I'd like to retrieve and remove the next item from a Java 8 Stream
, without this Stream
getting closed.
Stream<Integer> integerStream = Stream.iterate( 0, x -> new Integer(x + 1) );
Integer zero = integerStream.getNext(); // 0
Integer one = integerStream.getNext(); // 1
...
这可能吗?
推荐答案
基于 Stuart's answer 和 Iterator-to-Stream 转换,我想出了以下快速而简单的包装类.它没有经过测试,也不是线程安全的,但它为我提供了我目前需要的东西 —删除和使用单个项目,同时保持 this 流打开".
Based on Stuart's answer and with an Iterator-to-Stream conversion, I came up with the following quick-and-dirty wrapper class. It's not tested, and it's not thread-safe, but it provides me with what I currently need — removing and using single items while keeping this stream "open".
PeelingStream<T>
提供了一个方法 T getNext()
来屏蔽 someWrappedStream.iterator()
的 终端流操作 语义:
PeelingStream<T>
provides a method T getNext()
that shields away someWrappedStream.iterator()
's terminal stream operation semantics:
public class PeelingStream<T> implements Stream<T> {
private Stream<T> wrapped;
public PeelingStream(Stream<T> toBeWrapped) {
this.wrapped = toBeWrapped;
}
public T getNext() {
Iterator<T> iterator = wrapped.iterator();
T next = iterator.next();
Iterable<T> remainingIterable = () -> iterator;
wrapped = StreamSupport.stream(remainingIterable.spliterator(),
false);
return next;
}
///////////////////// from here, only plain delegate methods
public Iterator<T> iterator() {
return wrapped.iterator();
}
public Spliterator<T> spliterator() {
return wrapped.spliterator();
}
public boolean isParallel() {
return wrapped.isParallel();
}
public Stream<T> sequential() {
return wrapped.sequential();
}
public Stream<T> parallel() {
return wrapped.parallel();
}
public Stream<T> unordered() {
return wrapped.unordered();
}
public Stream<T> onClose(Runnable closeHandler) {
return wrapped.onClose(closeHandler);
}
public void close() {
wrapped.close();
}
public Stream<T> filter(Predicate<? super T> predicate) {
return wrapped.filter(predicate);
}
public <R> Stream<R> map(Function<? super T, ? extends R> mapper) {
return wrapped.map(mapper);
}
public IntStream mapToInt(ToIntFunction<? super T> mapper) {
return wrapped.mapToInt(mapper);
}
public LongStream mapToLong(ToLongFunction<? super T> mapper) {
return wrapped.mapToLong(mapper);
}
public DoubleStream mapToDouble(ToDoubleFunction<? super T> mapper) {
return wrapped.mapToDouble(mapper);
}
public <R> Stream<R> flatMap(
Function<? super T, ? extends Stream<? extends R>> mapper) {
return wrapped.flatMap(mapper);
}
public IntStream flatMapToInt(
Function<? super T, ? extends IntStream> mapper) {
return wrapped.flatMapToInt(mapper);
}
public LongStream flatMapToLong(
Function<? super T, ? extends LongStream> mapper) {
return wrapped.flatMapToLong(mapper);
}
public DoubleStream flatMapToDouble(
Function<? super T, ? extends DoubleStream> mapper) {
return wrapped.flatMapToDouble(mapper);
}
public Stream<T> distinct() {
return wrapped.distinct();
}
public Stream<T> sorted() {
return wrapped.sorted();
}
public Stream<T> sorted(Comparator<? super T> comparator) {
return wrapped.sorted(comparator);
}
public Stream<T> peek(Consumer<? super T> action) {
return wrapped.peek(action);
}
public Stream<T> limit(long maxSize) {
return wrapped.limit(maxSize);
}
public Stream<T> skip(long n) {
return wrapped.skip(n);
}
public void forEach(Consumer<? super T> action) {
wrapped.forEach(action);
}
public void forEachOrdered(Consumer<? super T> action) {
wrapped.forEachOrdered(action);
}
public Object[] toArray() {
return wrapped.toArray();
}
public <A> A[] toArray(IntFunction<A[]> generator) {
return wrapped.toArray(generator);
}
public T reduce(T identity, BinaryOperator<T> accumulator) {
return wrapped.reduce(identity, accumulator);
}
public Optional<T> reduce(BinaryOperator<T> accumulator) {
return wrapped.reduce(accumulator);
}
public <U> U reduce(U identity,
BiFunction<U, ? super T, U> accumulator,
BinaryOperator<U> combiner) {
return wrapped.reduce(identity, accumulator, combiner);
}
public <R> R collect(Supplier<R> supplier,
BiConsumer<R, ? super T> accumulator, BiConsumer<R, R> combiner) {
return wrapped.collect(supplier, accumulator, combiner);
}
public <R, A> R collect(Collector<? super T, A, R> collector) {
return wrapped.collect(collector);
}
public Optional<T> min(Comparator<? super T> comparator) {
return wrapped.min(comparator);
}
public Optional<T> max(Comparator<? super T> comparator) {
return wrapped.max(comparator);
}
public long count() {
return wrapped.count();
}
public boolean anyMatch(Predicate<? super T> predicate) {
return wrapped.anyMatch(predicate);
}
public boolean allMatch(Predicate<? super T> predicate) {
return wrapped.allMatch(predicate);
}
public boolean noneMatch(Predicate<? super T> predicate) {
return wrapped.noneMatch(predicate);
}
public Optional<T> findFirst() {
return wrapped.findFirst();
}
public Optional<T> findAny() {
return wrapped.findAny();
}
}
一个小测试:
@Test
public void testPeelingOffItemsFromStream() {
Stream<Integer> infiniteStream = Stream.iterate(0, x -> x + 1);
PeelingStream<Integer> peelingInfiniteStream = new PeelingStream<>(infiniteStream);
Integer one = peelingInfiniteStream.getNext();
assertThat(one, equalTo(0));
Integer two = peelingInfiniteStream.getNext();
assertThat(two, equalTo(1));
Stream<Integer> limitedStream = peelingInfiniteStream.limit(3); // 2 3 4
int sumOf234 = limitedStream.mapToInt(x -> x.intValue()).sum();
assertThat(sumOf234, equalTo(2 + 3 + 4));
}
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本文标题为:从 Java 8 流中获取下一项
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