将 Jersey 项目(Rest Web 服务)运行到 tomcat

Running Jersey project (Rest web service) to tomcat(将 Jersey 项目(Rest Web 服务)运行到 tomcat)

本文介绍了将 Jersey 项目(Rest Web 服务)运行到 tomcat的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试遵循本指南:tutorial 但是当我在网络浏览器上执行它会返回错误:

I'm try to follow this guide: tutorial but when I execute on the web browser it returns an error:

HTTP Status 404 - /
type Status report
message /
description The requested resource (/rest.api/rest/hello) is not available.

我已经在我的 mac 上的/usr/local 中安装了 tomcat7,并在终端上使用 startup.sh 运行它.这是我的 web.xml 和 Hello.java

I have installed tomcat7 in /usr/local on my mac and ran it with startup.sh on the terminal. This is my web.xml and Hello.java

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>HelloRest</display-name>

<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
  <param-name>com.sun.jersey.config.property.packages</param-name>
  <param-value>rest.api</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
 <servlet-name>Jersey REST Service</servlet-name>
 <url-pattern>/rest/*</url-pattern>
</servlet-mapping>

package rest.api;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;

// POJO, no interface no extends

// The class registers its methods for the HTTP GET request using the @GET annotation. 
// Using the @Produces annotation, it defines that it can deliver several MIME types,
// text, XML and HTML. 

// The browser requests per default the HTML MIME type.

//Sets the path to base URL + /hello
@Path("/hello")
public class Hello {

// This method is called if TEXT_PLAIN is request
@GET
@Produces(MediaType.TEXT_PLAIN)
public String sayPlainTextHello() {
    return "Hello Jersey";
}

// This method is called if XML is request
@GET
@Produces(MediaType.TEXT_XML)
public String sayXMLHello() {
    return "<?xml version="1.0"?>" + "<hello> Hello Jersey" + "</hello>";
}

// This method is called if HTML is request
@GET
@Produces(MediaType.TEXT_HTML)
public String sayHtmlHello() {
    return "<html> " + "<title>" + "Hello Jersey" + "</title>"
            + "<body><h1>" + "Hello Jersey" + "</body></h1>" + "</html> ";
}

}

这是我的配置项目:

有什么建议吗?

推荐答案

web.xml中使用如下配置

    <servlet>
        <servlet-name>ServletAdaptor</servlet-name>
        <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>ServletAdaptor</servlet-name>
        <url-pattern>/rest/*</url-pattern>
    </servlet-mapping>

希望这会对你有所帮助.

hope this will help you.

这篇关于将 Jersey 项目(Rest Web 服务)运行到 tomcat的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!

本文标题为:将 Jersey 项目(Rest Web 服务)运行到 tomcat

基础教程推荐