How to Convert a Properties Object to JSON Object with JAXB(如何使用 JAXB 将属性对象转换为 JSON 对象)
问题描述
我想在 REST 应用程序中接受和响应 JSON 对象.我需要发送和接收的数据位于 .properties 文件中.我已经阅读了它们,现在位于 Properties
对象中(来自 java.util.Properties
).有没有办法在不实现新类的情况下编组和解组 Properties
对象?
I want to accept and respond JSON objects in a REST Application. The data I need to send and receive are in a .properties file. I have already read them and are now in a Properties
Object(From java.util.Properties
). Is there a way to marshal and unmarshal Properties
Objects, without implementing a new class?
我在 Weblogic 服务器中使用 Jax-rs API.
I am using Jax-rs API in a Weblogic server.
@POST
@Path("{id}")
@Produces(MediaType.APPLICATION_JSON)
@Consumes(MediaType.APPLICATION_JSON)
public JSONObject getbyID(@PathParam("id")JSONObject inputJsonObj) {
//marshalling and unmarshalling goes here
}
推荐答案
对WebLogic不太熟悉,所以不知道它用的是什么版本的Jersey(1.x还是2.x),但是用的是1.x.x 你可以简单地添加这个依赖项
Not too familiar with WebLogic, so I don't know what version of Jersey it used (1.x or 2.x), but with the 1.x you can simply add this dependency
<dependency>
<groupId>com.sun.jersey</groupId>
<artifactId>jersey-json</artifactId>
<version>${jersey-version}</version>
</dependency>
这将取决于杰克逊.Jackson 已经将 Properties
对象反序列化并序列化为 JSON 对象.
which will depend on Jackson. Jackson already deserializes and serializes the Properties
object to a JSON object.
这是一个简单的测试
资源
@Path("/properties")
public class PropertiesResource {
@GET
@Produces(MediaType.APPLICATION_JSON)
public Response getProperties() throws Exception {
FileInputStream fis = new FileInputStream("test.properties");
Properties props = new Properties();
props.load(fis);
return Response.ok(props).build();
}
@POST
@Consumes(MediaType.APPLICATION_JSON)
public Response postProperties(Properties properties) {
StringBuilder builder = new StringBuilder();
for (String key: properties.stringPropertyNames()) {
builder.append(key).append("=")
.append(properties.getProperty(key)).append("
");
}
return Response.created(null).entity(builder.toString()).build();
}
}
测试
public void testMyResource() throws Exception {
ClientConfig config = new DefaultClientConfig();
config.getClasses().add(JacksonJsonProvider.class);
config.getFeatures().put(JSONConfiguration.FEATURE_POJO_MAPPING,
Boolean.TRUE);
Client c = Client.create(config);
WebResource resource = c.resource(Main.BASE_URI).path("properties");
String json = resource.accept("application/json").get(String.class);
System.out.println(json);
FileInputStream fis = new FileInputStream("test.properties");
Properties props = new Properties();
props.load(fis);
String postResponse
= resource.type("application/json").post(String.class, props);
System.out.println(postResponse);
}
结果:
// from get
{"prop3":"value3","prop2":"value2","prop1":"value1"}
// from post
prop3=value3
prop2=value2
prop1=value1
配置方面,只需要配置POJOMapping Feature并注册Jackson提供者
For the configuration, you just need to configure the POJOMapping Feature and register the Jackson provider
程序化
public class JerseyApplication extends ResourceConfig {
public JerseyApplication() {
packages(...);
getProviderClasses().add(JacksonJsonProvider.class);
getFeatures().put(JSONConfiguration.FEATURE_POJO_MAPPING, Boolean.TRUE);
}
}
web.xml
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
<小时>
使用 Jersey 2.x,它稍微简单一些.我们只需要这个提供者
With Jersey 2.x, it's a little bit simpler. We just need this provider
<dependency>
<groupId>com.fasterxml.jackson.jaxrs</groupId>
<artifactId>jackson-jaxrs-json-provider</artifactId>
<version>2.4.0</version>
</dependency>
并注册相同的JacksonJaxbJsonProvider
(虽然包不同,但类名相同).无需 Pojo 映射功能.
And register the same JacksonJaxbJsonProvider
(though different package, the class name is the same). No Pojo Mapping Feature needed.
注意:在这两种情况下,都有两个 Jackson 提供程序,一个 JacksonJsonProvider
和一个 JacksonJaxbJsonProvider
.如果您希望 pojo 的编组依赖于 JAXB 注释,那么您应该注册后者.
Note: In both cases, there are two Jackson providers, a JacksonJsonProvider
and a JacksonJaxbJsonProvider
. If you want the marshalling of pojos to depend on JAXB annotations, then you should register the latter.
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本文标题为:如何使用 JAXB 将属性对象转换为 JSON 对象
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