使用 JAXB 处理设计不佳的 XML

Dealing with poorly designed XML with JAXB(使用 JAXB 处理设计不佳的 XML)

本文介绍了使用 JAXB 处理设计不佳的 XML的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我目前正在使用 JAXB 替换旧系统,但在解析 XML 时遇到了问题.系统的第一个要求是它必须是插入式替换,因此我无法修改 XML 的格式.下面是给我带来麻烦的 XML 部分.

I'm currently working on replacing a legacy system with JAXB and I'm running into problem with parsing the XML. The number one requirement of the system is that it must be a drop-in replacement so I cannot modify the format of the XML. Below is the XML section that is giving me trouble.

<xx>
    <s1>
        <X>-9999</X>
        <Y>-9999</Y>
    </s1>
    <s2>
        <X>-9999</X>
        <Y>-9999</Y>
   </s2>
</xx>

XML 的问题是所有 s# 对象都完全相同,最多可以有 256 个.JAXB 中有没有办法注释这样的标签,还是我必须创建 256 个单独的注释?任何帮助将不胜感激.

The issue with the XML is that all of the s# objects are the exact same and there can be up to 256 of them. Is there a way in JAXB to annotate such a tag or do I have to create 256 separate annotations? Any help would be most appreciated.

这里是 xx 对象的 java 代码.注意:该对象最初是在理解只有 2 个 s# 对象的情况下进行编程的,但此后发生了变化.

Here is the java code for the xx object. Note: the object was originally programmed with the understanding that there would only be 2 s# objects, but that since has changed.

@XmlRootElement(name="xx")

public class XMLXx implements Serializable {

    private static final long serialVersionUID = 4064597372833234503L;

    private XMLSite siteOne;
    private XMLSite siteTwo;

    @XmlElement(name="s1")
    public XMLSite getSiteOne() {
        return siteOne;
    }

    public void setSiteOne(XMLSite s1) {
        this.siteOne = s1;
    }

    @XmlElement(name="s2")
    public XMLSite getSiteTwo() {
        return siteTwo;
    }

    public void setSiteTwo(XMLSite s2) {
        this.siteTwo = s2;
    }
}

这里是 XMLSite 对象:

And here is the XMLSite object:

public class XMLSite implements Serializable {

    private static final long serialVersionUID = -4374405403222014476L;

    private Integer x;
    private Integer y;

    @XmlElement(name="X")
    public Integer getX() {
        return x;
    }

    public void setX(Integer x) {
        this.x = x;
    }

    @XmlElement(name="Y")
    public Integer getY() {
        return y;
    }

    public void setY(Integer y) {
        this.y = y;
    }
}

推荐答案

如果你想把 s# 处的项作为一个集合来处理:

If you want to handle at the s# items as a collection:

import java.io.Serializable;
import java.util.List;

import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement(name="xx")
public class XMLXx implements Serializable {

    private static final long serialVersionUID = 4064597372833234503L;

    private List<XMLSite> sites;

    @XmlElement(name="s")
    public List<XMLSite> getSites() {
        return sites;
    }

    public void setSites(List<XMLSite> sites) {
        this.sites = sites;
    }

}

然后你可以做一些事情,比如欺骗 JAXB,让他们认为所有元素(s1s2 等)实际上都称为 s:

Then you could do something like to fool JAXB into thinking all the elements (s1, s2, etc) are actually called s:

import java.io.FileInputStream;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.Unmarshaller;
import javax.xml.stream.XMLInputFactory;
import javax.xml.stream.XMLStreamReader;
import javax.xml.stream.util.StreamReaderDelegate;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(XMLXx.class);

        XMLInputFactory xif = XMLInputFactory.newInstance();
        XMLStreamReader xsr = xif.createXMLStreamReader(new FileInputStream("input.xml"));
        xsr = new SiteStreamReaderDelegate(xsr);

        Unmarshaller unmarshaller = jc.createUnmarshaller();
        XMLXx object = (XMLXx) unmarshaller.unmarshal(xsr);
        System.out.println(object.getSites().size());

    }

    private static class SiteStreamReaderDelegate extends StreamReaderDelegate {

        public SiteStreamReaderDelegate(XMLStreamReader xsr) {
            super(xsr);
        }

        @Override
        public String getLocalName() {
            String localName = super.getLocalName();
            if(localName.startsWith("s")) {
                return "s";
            }
            return localName;
        }

    }
}

类似的例子见:

  • http://bdoughan.blogspot.com/2010/12/case-insensitive-unmarshalling.html

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本文标题为:使用 JAXB 处理设计不佳的 XML

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