JAXB - 从 url 解组

JAXB - unmarshalling from url(JAXB - 从 url 解组)

问题描述

我正在尝试显示来自该站点的游戏的标题和 ID:http://thegamesdb.net/api/GetGame.php?id=2

I'm tryting to display title and id of game from this site: http://thegamesdb.net/api/GetGame.php?id=2

当我从这个网址解组时:http://www.w3schools.com/xml/note.xml 一切正常，但这里只有一个对象，而不是列表.所以我现在有问题.我正在阅读 Google 的一些教程和示例，并编写了以下代码:

When I was unmarshalling from this url: http://www.w3schools.com/xml/note.xml it was all ok, but here was just one object, not a list. So I'm having problem now. I was reading some tutorials and examples from Google and I made this code:

Data.java:

@XmlRootElement( name = "Data" )
@XmlAccessorType (XmlAccessType.FIELD)
public class Data {
    @XmlElement(name = "Game")
    List<Game> games;

    public List<Game> getGames() {
        return games;
    }

    public void setGames(List<Game> games) {
        this.games = games;
    }
}

Game.java 文件:

Game.java file:

@XmlRootElement(name = "Game")
@XmlAccessorType (XmlAccessType.FIELD)
public class Game {
    private int id;
    private String gameTitle;

    public int getId(){
        return id;
    }

    public void setId(int id){
        this.id = id;
    }

    public String getGameTitle(){
        return gameTitle;
    }

    public void setGameTitle(String gameTitle){
        this.gameTitle = gameTitle;
    }
}

控制器:

@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView home(Locale locale) throws MalformedURLException {
    ModelAndView model = new ModelAndView("index");
    JAXBExample test = new JAXBExample();
    Game customer = test.readXML();
    model.addObject("customer", customer);
    return model;
}

JAXBExample.java:

JAXBExample.java:

public class JAXBExample {
    public Game readXML() throws MalformedURLException {
        Data customer = null;
        Game game = null;
        try {
            JAXBContext jaxbContext  = JAXBContext.newInstance(Data.class);
            URL url = new URL("http://thegamesdb.net/api/GetGame.php?id=2");
            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
            customer = (Data) jaxbUnmarshaller.unmarshal(url);
            List<Game> games = customer.getGames();
            game = games.get(0);
        } catch (JAXBException e) {
            e.printStackTrace();
        }
        return game;
    }
}

还有 index.jsp:

And index.jsp:

<%@ taglib uri="http://tiles.apache.org/tags-tiles" prefix="tiles"%>

<tiles:insertDefinition name="defaultTemplate">
    <tiles:putAttribute name="body">
        Name: ${customer.gameTitle}<br />
        Id: ${customer.id}<br />
    </tiles:putAttribute>
</tiles:insertDefinition>

但我的代码不起作用.有人可能知道我做错了什么?因为结果我得到了:

But my code isn't working. Somebody have maybe idea what I'm doing wrong? Because as result I just get:

Name:
Id: 

仅此而已.

推荐答案

你的注释唯一有问题的是

The only thing that is wrong with your annotation is

public class Game {
  private int id;
  @XmlElement(name = "GameTitle") //You need to add this since first letter is uppercase, otherwise the GameTitle will not unmarshall.
  private String gameTitle; 
  ... your code ...
}

那么为什么其余的都不起作用?

服务器返回 HTTP 响应代码:403 用于 URL:http://thegamesdb.net/api/GetGame.php?id=2

Server returned HTTP response code: 403 for URL: http://thegamesdb.net/api/GetGame.php?id=2

403 = 禁止

解决方案(让服务器认为你是浏览器)

Solution (make the server believe you are a browser)

URL url = new URL("http://thegamesdb.net/api/GetGame.php?id=2");
HttpURLConnection http = (HttpURLConnection) url.openConnection(); 
http.addRequestProperty("User-Agent", "Mozilla/4.76"); 
InputStream is = http.getInputStream();
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
customer = (Data) jaxbUnmarshaller.unmarshal(is);
List<Game> games = customer.getGames();
game = games.get(0);

注意:尝试 catch final、关闭流并检查 NullPointer 超出了本示例的范围，由用户决定.

Note: Try catch final, close streams and checking for NullPointer is beyond this example and up to user.

这篇关于JAXB - 从 url 解组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！