How to compute `ulp`when `Math.ulp` is missing?(当`Math.ulp`丢失时,如何计算`ulp`?)
问题描述
我需要给定双精度值的ulp,但由于我是为代号1开发的,所以没有提供ulp(double)
。有没有人知道用Java计算ulp
的有效算法?Codename One仅提供了Math
类中的一些方法(javadoc用于CN1版本),并且填补了MathUtil中的一些空白。
作为一种解决办法,我使用此(不正确的)代码,直到我找到一个可用的替代代码:
private double ulp(double y) {
return y/1e15;
}
编辑:我为review发布了我自己的代码。以防其他人需要这个。
推荐答案
好的,因为我没有找到可用的替代品(ApacheHarmony和OpenJDK最终都使用了CN1上没有的本机方法),所以我编写了自己的版本(针对OpenJDK-Version进行了测试)。以防万一有人需要。
至于代号一:我向MathUtil类提交了一个补丁,所以希望迟早会添加这个补丁。
/*
* use a precalculated value for the ulp of Double.MAX_VALUE
*/
private static final double MAX_ULP = 1.9958403095347198E292;
/**
* Returns the size of an ulp (units in the last place) of the argument.
* @param d value whose ulp is to be returned
* @return size of an ulp for the argument
*/
@Override
public double ulp(double d) {
if (Double.isNaN(d)) {
// If the argument is NaN, then the result is NaN.
return Double.NaN;
}
if (Double.isInfinite(d)) {
// If the argument is positive or negative infinity, then the
// result is positive infinity.
return Double.POSITIVE_INFINITY;
}
if (d == 0.0) {
// If the argument is positive or negative zero, then the result is Double.MIN_VALUE.
return Double.MIN_VALUE;
}
d = Math.abs(d);
if (d == Double.MAX_VALUE) {
// If the argument is Double.MAX_VALUE, then the result is equal to 2^971.
return MAX_ULP;
}
return nextAfter(d, Double.MAX_VALUE) - d;
}
@Override
public double copySign(double x, double y) {
return com.codename1.util.MathUtil.copysign(x,y);
}
private boolean isSameSign(double x, double y) {
return copySign(x, y) == x;
}
/**
* Returns the next representable floating point number after the first
* argument in the direction of the second argument.
*
* @param start starting value
* @param direction value indicating which of the neighboring representable
* floating point number to return
* @return The floating-point number next to {@code start} in the
* direction of {@direction}.
*/
@Override
public double nextAfter(final double start, final double direction) {
if (Double.isNaN(start) || Double.isNaN(direction)) {
// If either argument is a NaN, then NaN is returned.
return Double.NaN;
}
if (start == direction) {
// If both arguments compare as equal the second argument is returned.
return direction;
}
final double absStart = Math.abs(start);
final double absDir = Math.abs(direction);
final boolean toZero = !isSameSign(start, direction) || absDir < absStart;
if (toZero) {
// we are reducing the magnitude, going toward zero.
if (absStart == Double.MIN_VALUE) {
return copySign(0.0, start);
}
if (Double.isInfinite(absStart)) {
return copySign(Double.MAX_VALUE, start);
}
return copySign(Double.longBitsToDouble(Double.doubleToLongBits(absStart) - 1L), start);
} else {
// we are increasing the magnitude, toward +-Infinity
if (start == 0.0) {
return copySign(Double.MIN_VALUE, direction);
}
if (absStart == Double.MAX_VALUE) {
return copySign(Double.POSITIVE_INFINITY, start);
}
return copySign(Double.longBitsToDouble(Double.doubleToLongBits(absStart) + 1L), start);
}
}
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本文标题为:当`Math.ulp`丢失时,如何计算`ulp`?
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