保持 GPS 服务有效并优化电池寿命

-I need a GPS fix every 10 min, so I think the best way to do it is to start the location service, get a fix (or timeout) and stop the service (with removeUpdates()). How can I have an application (or service or whatever) running this cycle every 10min and be sure it will continue as long as there is some battery left (even if device goes to sleep, it should wake it up every 10min to get a fix)? Is using AlarmManager a good idea?

-我可以期望电池使用这种方法可以使用一天吗?

-Can I expect the battery to last one day with this method?

我已经检查了 mytracks，但 gps 监听器似乎始终处于开启状态，并且预计电池电量持续不超过 5 小时.

I've checked mytracks but the gps listener seems always on and the battery is expected to last no more than 5h.

我还检查了 CWAC 位置轮询器，但它只检查了 removeUpdates() 超时并立即重新启动侦听器.它还使用唤醒锁，而在我的情况下，我认为 AlarmManager 可能是一个更好的主意.

I've also checked CWAC Location Poller but it does only removeUpdates() on timeout and restart the listener immediately. It also uses a wakelock while in my case I think an AlarmManager could be a better idea.

欢迎任何帮助/建议

推荐答案

你对我使用的警报管理器很满意

You are spot on with alarm manager I use

    Intent serviceIntent = new Intent(this, TrackerService.class);
    mPendingIntent = PendingIntent.getService(this, 0, serviceIntent,
            PendingIntent.FLAG_UPDATE_CURRENT);

    AlarmManager alarmManager = (AlarmManager) getSystemService(ALARM_SERVICE);

    alarmManager.cancel(mPendingIntent);
    alarmManager.setInexactRepeating(AlarmManager.RTC_WAKEUP,
                System.currentTimeMillis(), interval, mPendingIntent);

在类似的应用中获取网络位置

in a similar app for getting network location

启动服务的间隔是毫秒

服务启动，获取位置并关闭

the service starts up, gets the location and closes

这比等待报告的活动服务更省电

this was MUCH more battery efficient that hanging around with an active service waiting for reports

我发布的代码首先取消了以前的警报，所以你不会得到超过 1 个 :)

that code i posted cancels the previous alarms first so you don't get more than 1 :)

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