如何在 ECB 模式下使用 DES 加密 Objective C 中的 NSString?

How to encrypt an NSString in Objective C with DES in ECB-Mode?(如何在 ECB 模式下使用 DES 加密 Objective C 中的 NSString?)

问题描述

我正在尝试在 iPhone 上的 Objective C 中加密一个 NSString.至少当我编码 "us=foo;pw=bar;pwAlg=false;" 时，我不想得到像 "TmsbDaNG64lI8wC6NLhXOGvfu2IjLGuEwc0CzoSHnrs=" 这样的字符串通过使用这个键:testtest".

I am trying to encrypt an NSString in Objective C on the iPhone. At least I wan't to get a string like "TmsbDaNG64lI8wC6NLhXOGvfu2IjLGuEwc0CzoSHnrs=" when I encode "us=foo;pw=bar;pwAlg=false;" by using this key: "testtest".

我现在的问题是，CCCrypt 总是返回4300 - 参数错误"，我不知道为什么.

My problem for now is, that CCCrypt always returns "4300 - Parameter error" and I have no more idea why.

这是我的代码(5 小时 google 和 try'n'error 的结果):

This is my code (the result of 5 hours google and try'n'error):

NSString *token = @"us=foo;pw=bar;pwAlg=false;";
NSString *key = @"testtest";

const void *vplainText;
size_t plainTextBufferSize;

plainTextBufferSize = [token length];
vplainText = (const void *) [token UTF8String];

CCCryptorStatus ccStatus;
uint8_t *bufferPtr = NULL;
size_t bufferPtrSize = 0;
size_t *movedBytes;

bufferPtrSize = (plainTextBufferSize + kCCBlockSize3DES) & ~(kCCBlockSize3DES - 1);
bufferPtr = malloc( bufferPtrSize * sizeof(uint8_t));
memset((void *)bufferPtr, 0x0, bufferPtrSize);
// memset((void *) iv, 0x0, (size_t) sizeof(iv));


NSString *initVec = @"init Vec";
const void *vkey = (const void *) [key UTF8String];
const void *vinitVec = (const void *) [initVec UTF8String];

ccStatus = CCCrypt(kCCEncrypt,
                   kCCAlgorithmDES,
                   kCCOptionECBMode,
                   vkey, //"123456789012345678901234", //key
                   kCCKeySizeDES,
                   NULL,// vinitVec, //"init Vec", //iv,
                   vplainText, //"Your Name", //plainText,
                   plainTextBufferSize,
                   (void *)bufferPtr,
                   bufferPtrSize,
                   movedBytes);

NSString *result;
NSData *myData = [NSData dataWithBytes:(const void *)bufferPtr length:(NSUInteger)movedBytes];
result = [myData base64Encoding];

推荐答案

ECB 模式下的 DES 加密使用 8 字节的块大小，并单独对每个块进行编码.问题是您的输入字符串没有平均分成 8 个字节，并且密码器不知道如何处理最终的非 8 字节块.

DES encryption in ECB mode uses an 8 byte block size, and encodes each blocks individually. The problem is that your input string doesn't divide into 8 bytes equally and the cryptor doesn't know what to do with the final non 8 byte block.

修复方法是允许密码器通过将 kCCOptionPKCS7Padding 添加到 CCCrypt 的选项来填充最终块.例如(来自 NSData 加密类别的片段):

The fix is to allow the cryptor to pad the final block by adding kCCOptionPKCS7Padding to the options to CCCrypt. eg (snippet from an NSData encryption category):

CCCryptorStatus cryptStatus = CCCrypt(kCCEncrypt, 
                                      kCCAlgorithmDES, 
                                      kCCOptionPKCS7Padding | kCCOptionECBMode,
                                      keyPtr, 
                                      kCCKeySizeDES,
                                      NULL, 
                                      [self bytes], 
                                      dataLength,
                                      buffer, 
                                      bufferSize
                                      &numBytesEncrypted);

查看此帖子，了解有关填充算法的更多详细信息.希望这会有所帮助.

Take a look at this post for more details regarding padding algorithms. Hope this helps.

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