gdb 中的 nil 未定义为 0x0?

nil in gdb is not defined as 0x0?(gdb 中的 nil 未定义为 0x0?)

问题描述

我正在使用 gdb(在 Xcode 内部)逐步完成一些简单的 Objective-C 代码，并注意到一些奇怪的东西.这是相关的片段:

I was stepping through some simple Objective-C code with gdb (inside of Xcode) and noticed something strange. Here is the relevant snippet:

NSString *s = nil;
int x = (s == nil);

正如我所料，这两行之后x的值是1.奇怪的是，如果我在 gdb 中尝试类似的东西，它就不一样了:

As I'd expect, the value of x after these two lines is 1. Strangely, if I try something similar in gdb, it doesn't work the same:

(gdb) print ret
$1 = (NSString *) 0x0
(gdb) print (int)(ret==nil)
$2 = 0
(gdb) print nil
$3 = {<text variable, no debug info>} 0x167d18 <nil>

似乎 gdb 对 nil 有一些定义，而不是 Objective-C 使用的 (0x0).有人能解释一下这里发生了什么吗?

It seems like gdb has some definition for nil other than what objective-C uses (0x0). Can someone explain what's going on here?

推荐答案

当你的代码被编译时，nil 是一个预处理器常量，定义为 __null (a用作 NULL)、0L 或 0 的特殊 GCC 变量:

When your code is being compiled, nil is a preprocessor constant defined to be either __null (a special GCC variable that serves as NULL), 0L, or 0:

<objc/objc.h>
#ifndef nil
#define nil __DARWIN_NULL /* id of Nil instance */
#endif

<sys/_types.h>
#ifdef __cplusplus
#ifdef __GNUG__
#define __DARWIN_NULL __null
#else /* ! __GNUG__ */
#ifdef __LP64__
#define __DARWIN_NULL (0L)
#else /* !__LP64__ */
#define __DARWIN_NULL 0
#endif /* __LP64__ */
#endif /* __GNUG__ */
#else /* ! __cplusplus */
#define __DARWIN_NULL ((void *)0)
#endif /* __cplusplus */

那么，gdb 在运行时获取的 nil 是从哪里来的呢?您可以从 gdb 给出的消息中看出 nil 是位于该地址的变量的名称:

So, where does the nil that gdb picks up at runtime come from? You can tell from the message gdb gives that nil is the name of a variable located at that address:

(gdb) p nil
$1 = {<text variable, no debug info>} 0x20c49ba5da6428 <nil>
(gdb) i addr nil
Symbol "nil" is at 0x20c49ba5da6428 in a file compiled without debugging.

不出所料，它的值是0:

(gdb) p *(long *)nil
$2 = 0
(gdb) x/xg nil
0x20c49ba5da6428 <nil>: 0x0000000000000000

这个变量从何而来?GDB 可以告诉我们:

Where does this variable come from? GDB can tell us:

(gdb) i shared nil
  3 Foundation        F -                 init Y Y /System/Library/Frameworks/Foundation.framework/Versions/C/Foundation at 0x20c49ba5bb2000 (offset 0x20c49ba5bb2000)

确实，当我们检查Foundation中定义的符号时，我们发现nil:

Indeed, when we check the symbols defined in Foundation, we find nil:

$ nm -m /System/Library/Frameworks/Foundation.framework/Foundation | grep nil$
00000000001f4428 (__TEXT,__const) external _nil

这篇关于gdb 中的 nil 未定义为 0x0?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！