Proper way to convert char* to NSString without initWithCString?(在没有 initWithCString 的情况下将 char* 转换为 NSString 的正确方法?)
问题描述
我正在将 SQLite3 数据库中的结果列表提取到 UITableView
中.我从数据库中提取文本的代码是这样的:
I'm pulling a listing of results from a SQLite3 database into a UITableView
. The code where I pull text from the database is like so:
char *menuNameChars = (char *) sqlite3_column_text(statement, 1);
NSString *menuName = [[NSString alloc] initWithUTF8String:menuNameChars];
NSLog(@"Retrieved %s,%@ from DB.", menuNameChars, menuName);
当我使用 initWithUTF8String
时,有时会从数据库中正确复制信息.但有时,信息可以从 char*
正确显示,但不能从 NSString
:
When I use initWithUTF8String
, sometimes the information is copied properly from the database. Sometimes though, the information is displayed properly from the char*
, but not from the NSString
:
2011-10-24 22:26:54.325 [23974:207] Retrieved Cravin Chicken Sandwich – Crispy, (null) from DB.
2011-10-24 22:26:54.327 [23974:207] Retrieved Cravin Chicken Sandwich – Roast, (null) from DB.
2011-10-24 22:26:54.331 [23974:207] Retrieved Jr Chicken Sandwich, Jr Chicken Sandwich from DB.
2011-10-24 22:26:54.337 [23974:207] Retrieved Prime-Cut Chicken Tenders - 3 Piece, Prime-Cut Chicken Tenders - 3 Piece from DB.
现在,如果我将 initWithUTF8String
替换为 initWithCString
,则代码可以完美运行.但是,XCode 4.2 告诉我 initWithCString
已被弃用.我知道的足够了解我不想使用已弃用的代码,但如果 initWithUTF8String
不起作用,我应该使用什么?
Now, if I replace initWithUTF8String
with initWithCString
, the code works perfectly. However, XCode 4.2 tells me that initWithCString
has been deprecated. I know enough to understand I don't want to use deprecated code, but if initWithUTF8String
isn't working, what should I use?
推荐答案
我可以看到您的第一行日志中的破折号(Retrieved Cravin Chicken Sandwich ...
)不是简单的 ASCIIHYPHEN-MINUS
(U+002D, UTF-8 2D).这是一个 Unicode EN DASH
字符(U+2013,UTF-8 E2 80 93).第二行也一样.我的猜测是它们在您的数据库中的编码不正确.如果你给 -[NSString initWithUTF8String:]
一个不是有效 UTF-8 的 C 字符串,它会返回 nil
.
I can see that the dash in your first log line (Retrieved Cravin Chicken Sandwich ...
) isn't a simple ASCII HYPHEN-MINUS
(U+002D, UTF-8 2D). It's a Unicode EN DASH
character (U+2013, UTF-8 E2 80 93). Same for the second line. My guess is they're encoded incorrectly in your database. If you give -[NSString initWithUTF8String:]
a C-string that's not valid UTF-8, it returns nil
.
尝试打印 menuNameChars
的十六进制转储.您可以通过在调用 sqlite3_column_text
之后的行上设置断点来实现.到达断点时,右键单击/控制单击堆栈框架窗口中的 menuNameChars
并选择 View memory of *menuNameChars"
(注意 *
).
Try printing a hex dump of menuNameChars
. You can do that by setting a breakpoint on the line after the call to sqlite3_column_text
. When the breakpoint is reached, right-click/control-click menuNameChars
in your stack frame window and choose View memory of "*menuNameChars"
(note the *
).
这篇关于在没有 initWithCString 的情况下将 char* 转换为 NSString 的正确方法?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:在没有 initWithCString 的情况下将 char* 转换为 NSS
基础教程推荐
- UIWebView 委托方法 shouldStartLoadWithRequest:在 WKWebView 中等效? 2022-01-01
- 如何在 UIImageView 中异步加载图像? 2022-01-01
- 当从同一个组件调用时,两个 IBAction 触发的顺序是什么? 2022-01-01
- android 应用程序已发布,但在 google play 中找不到 2022-01-01
- 如何在 iPhone 上显示来自 API 的 HTML 文本? 2022-01-01
- 在 gmail 中为 ios 应用程序检索朋友的朋友 2022-01-01
- 如何在没有IB的情况下将2个按钮添加到右侧的UINavigationbar? 2022-01-01
- Android:对话框关闭而不调用关闭 2022-01-01
- 如何让对象对 Cocos2D 中的触摸做出反应? 2022-01-01
- Kivy Buildozer 无法构建 apk,命令失败:./distribute.sh -m “kivy"d 2022-01-01