如何使用 Init() 方法在 LibGDX 中重新启动屏幕?

How to restart screen in LibGDX using Init() methods?(如何使用 Init() 方法在 LibGDX 中重新启动屏幕?)

问题描述

我在 LibGDX 中创建了一个具有多个屏幕的简单游戏.我想在触摸重启按钮后重启某个屏幕，但我不知道该怎么做.我对此进行了一些研究，所有答案都导致我没有在 show() 中加载我的资产，而是在我不太熟悉的 init() 方法中加载.我想知道如何使用这个 init() 方法重新启动屏幕.到目前为止，我将大部分初始化都放在了构造函数中，有些在诸如 restartButton() 方法之类的方法中进行了初始化.我的代码中的任何其他更正或改进将不胜感激.这是我的代码片段:

I created a simple game in LibGDX that has multiple screens. I want to restart a certain screen after touching a restart button but I'm not sure how to do that. I made some research about this and all answers lead to not loading my assets in show() but rather in an init() method that I am not really familiar with. I want to know how can I restart a screen using this init() method. As of now I put most of my initialization in the constructor and some were initialized in methods such as the restartButton() method. Any other corrections or improvements in my code will be highly appreciated. Here is a snippet of my code:

public class LevelOneScreen implements Screen {

public MainShooter app;
private Stage stage;
private Stage stageCoin;
private Stage stageScore;
private Stage stageEnemies;
private Stage stageFX;
private Stage stageButton;

public Image aImage;
public Image bImage;
public Image cImage;
public Image dImage;

public Array<AntAnimation> AntAnimate;
public Array<CrumbAnimation> CrumbAnimate;
public Array<CoinAnimation> CoinAnimate;

public Texture firstTex;
public Texture secTex;
public Texture thirdTex;
public Texture fourthTex;


 public LevelOneScreen(final MainShooter app){

 this.app = app;
 this.stage = new Stage(new StretchViewport(app.screenWidth, app.screenHeight, app.camera));
 this.stageCoin = new Stage(new StretchViewport(app.screenWidth, app.screenHeight, app.camera));
 this.stageScore = new Stage(new StretchViewport(app.screenWidth, app.screenHeight, app.camera));
this.stageEnemies = new Stage(new StretchViewport(app.screenWidth, app.screenHeight, app.camera));
this.stageFX = new Stage(new StretchViewport(app.screenWidth, app.screenHeight, app.camera));
this.stageButton = new Stage(new StretchViewport(app.screenWidth, app.screenHeight, app.camera));

AntAnimate = new Array<AntAnimation>();
CrumbAnimate = new Array<CrumbAnimation>();
CoinAnimate = new Array<CoinAnimation>();

restartButton();
levelOneBackground();
coinScore();


}


public void show() {


    inputMultiplexer = new InputMultiplexer();
    inputMultiplexer.addProcessor(stageCoin);
    inputMultiplexer.addProcessor(stageScore);
    inputMultiplexer.addProcessor(stageEnemies);
    inputMultiplexer.addProcessor(stageFX);
    inputMultiplexer.addProcessor(stageButton);

    Gdx.input.setInputProcessor(inputMultiplexer);

   }

   public void levelOneBackGround(){
   //code for the background 
   }


   public void coinScore(){
   //code for coinScore
   }

   public void restartButton(){
   firstTex = MainShooter.manager.get("button.png", Texture.class);
   aImage = new Image(firstTex);
   stageButton.addActor(aImage);
   aImage.addListener(new ActorGestureListener() {
        public void touchDown(InputEvent event, float x, float y, int pointer, int button) {

        // Creating new LevelOneScreen somehow affects the fps of my game.
        app.setScreen(new LevelOneScreen(app));


        }});
   }


//some other codes like dispose, hide, etc.

}

此编辑是对 IronMonkey 提供的答案的回应，该答案似乎可以解决问题，但需要额外的代码.这里的问题是，无论何时重新启动游戏，重新启动屏幕的演员都位于前一个屏幕(重新启动之前的屏幕)上的演员之上.这是我的新代码片段，展示了如何使用我的 GameInit() 重新启动游戏:

This edit is a response to an answer provided by IronMonkey which seems to solve the problem but needs additional code. The problem here is that whenever the game is restarted, the actors from the restarted screen is on top of the actors on the previous screen(the screen before restarting). Here is a new snippet of my code showing how to restart the game using my GameInit():

     public void GameInit(){
     levelOneBackground();
     scoreInt = 0;
     coinInt = 0;
}


public void levelOneBackground(){

        Runnable runAntAct1 = new Runnable(){
            public void run(){
                antAct1();
            }
        };
        Runnable runAntAct2= new Runnable(){
            public void run(){
                antAct2();
            }
        };
        Runnable runAntAct3 = new Runnable(){
            public void run(){
                antAct3();
            }
        };
        Runnable runCoins = new Runnable(){
            public void run(){
                coinScattered();
            }
        };
        levelOneTexture =  CoinAssets.manager.get("woodenTable.png",Texture.class);
        levelOneImage = new Image(levelOneTexture);
        levelOneImage.setSize(app.screenWidth,app.screenHeight);
        levelOneImage.setPosition(0,0);
        stage.addActor(levelOneImage);
        levelOneImage.addAction(sequence(run(runAct1),delay(2f),run(runAct2),delay(2f),run(runAct3),delay(2f),run(runCoins)));


}

public void restartButton(){
     //some code for the position, size, texture of the button.
     restartButton.addListener(new ActorGestureListener() {
            public void touchDown(InputEvent event, float x, float y, int pointer, int button) {
                GameInit();}});
}


public void antAct1(){
         for(int i = 1; i < 4; i++){AntAnimate.add(new AntAnimation(app));}

         AntAnimate.get(1).setPosition(x,y);
         stageEnemies.addActor.(AntAnimate.get(1));
         AntAnimate.get(1).addAction(//some actions);

          AntAnimate.get(2).setPosition(x,y);
         stageEnemies.addActor.(AntAnimate.get(2));
         AntAnimate.get(2).addAction(//some actions);

          AntAnimate.get(3).setPosition(x,y);
         stageEnemies.addActor.(AntAnimate.get(3));
         AntAnimate.get(3).addAction(//some actions);

}

public void antAct2(){
     //almost the same with antAct1()
}

public void antAct3(){
     //almost the same with antAct1()
}

public void coinScattered(){
     //almost the same with antAct1()
}

推荐答案

第一次显示屏幕时会自动调用show().

show() is called automatically when the screen is first shown.

init() 方法是您自己创建的.你可以随心所欲地称呼它.您不应该在 init() 中加载所有资产，只需设置所有内容， score = 0, player.setPosition(0,0) 等.

The init() method is one you create yourself. You can call it whatever you want. You should not load all the assets in init() just set everything up, score = 0, player.setPosition(0,0) etc.

因此，当您第一次调用 init() 时，您设置了所有变量.当您再次调用 init() 时，您再次设置它们.(重新设置)

So when you first call init() you set all variables. When you call init() again you set them again. (reset)

问题编辑后:

在从 GameInit() 调用的方法中，您加载已加载的文件并将演员添加到这些演员已经存在并因此现在重叠的阶段.您还可以添加操作并创建已创建的对象.

In the methods called from GameInit() you load files that are already loaded and add actors to stages where those actors are already there and therefore now overlapping. You also add actions and create objects already created.

所有 GameInit() 应该做的是为那些已经创建的对象设置值.所以基本上:

All GameInit() should do is set values for those already created objects. So basically:

private void GameInit(){
      AntAnimate.get(1).setPosition(x,y);
      AntAnimate.get(2).setPosition(x,y);
      AntAnimate.get(3).setPosition(x,y);
      levelOneImage.setPosition(0,0);
      scoreInt = 0;
      coinInt = 0;
}

不应多次加载和创建对象.尝试添加我的 GameInit() 方法，调用它 GameReset() 并从重置按钮调用它.

Loading and creation of objects should not be done more than once. Try just adding my GameInit() method, call it GameReset() and call it from your reset button.

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