沃梦达 / 编程问答 / php问题 / 正文

Laravel Eloquent::Find() 返回具有现有 ID 的 NULL

Laravel Eloquent::Find() returning NULL with an existing ID(Laravel Eloquent::Find() 返回具有现有 ID 的 NULL)

本文介绍了Laravel Eloquent::Find() 返回具有现有 ID 的 NULL的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

这很简单,因为它是最基本的东西,但我不知道我错过了什么:

It's pretty straightforward as it's the most basic thing but I don't know what I'm missing:

拥有一个名为 Site

我正在使用 Eloquent ORM,所以当我调用(在控制器中)时

I'm using Eloquent ORM, so when I call (in a controller)

$oSite = Site::find(1)

然后

var_dump($oSite);

它返回NULL的值.

但是当我检查数据库时,表'sites'实际上包含以下项目:

But when I check the database, the table 'sites' actually contains the following item:

id: 1
user_id: 1
name: test

在我的 Site model 我有以下代码:

In my Site model I have the following code:

use IlluminateDatabaseEloquentModelNotFoundException;

 Class Site extends Eloquent {

        protected $table = 'sites';

        protected $fillable = ['user_id', 'name'];
 }

相反,如果我使用以下内容收集项目:

Instead, if I gather the item with the following:

$oSite = DB::table('sites')
                ->where('id', 1)
                ->first();

它有效,我得到了正确的寄存器.

It works and I get the correct register.

我做错了什么?我没有得到文档的哪一部分?

What I'm doing wrong? Which part of the documentation I didn't get?

型号代码可以在上面查看.

Model code can be checked above.

控制器:

use IlluminateSupportFacadesRedirect;
class SiteManagementController extends BaseController {

...

    public function deleteSite()
    {
        if (Request::ajax())
        {
            $iSiteToDelete = Input::get('siteId');

            $oSite = Site::find($iSiteToDelete);

            return var_dump($oSite);
        }
        else
        {
            return false;
        }
    }
}

编辑 2:(已解决)

无法正常工作的真正原因:

我的模型代码中最初如下:

use IlluminateDatabaseEloquentSoftDeletingTrait;
use IlluminateDatabaseEloquentModelNotFoundException;

Class Site extends Eloquent {

    protected $table = 'sites';

    use SoftDeletingTrait;

    protected $dates = ['deleted_at'];

    protected $fillable = ['user_id', 'name'];
}

问题是我在启动项目后添加了一个deleted_at"列,当我应用迁移时,我没有启用软删除.显然,我犯了第二个错误,忘记启用 'deleted_at' 可以为空,因此所有插入的时间戳都错误(0000-00-00 ...).

Problem was I added a 'deleted_at' column after I started the project and when I applied migrations, I didn't have softdeleting enabled. Obviously, I did a second error, forgetting to enable 'deleted_at' to be nullable, hence all inserts went had a wrong timestamp (0000-00-00 ...).

修复:

  1. deleted_at"列设为可为空.

将所有错误的deleted_at"时间戳设置为NULL.

Set all wrong 'deleted_at' timestamps to NULL.

推荐答案

检查您是否正确获取 Input::get('siteId').如果你得到它然后尝试将它转换为整数,即

Check you are getting Input::get('siteId') correctly. if you are getting it then try to convert it into integer i.e

$iSiteToDelete = intval(Input::get('siteId'));

这篇关于Laravel Eloquent::Find() 返回具有现有 ID 的 NULL的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!

本文标题为:Laravel Eloquent::Find() 返回具有现有 ID 的 NULL

基础教程推荐