如何使用坐标将标记移动 100 米

How to move a marker 100 meters with coordinates(如何使用坐标将标记移动 100 米)

问题描述

我有 2 个坐标.坐标 1 是人".坐标 2 是目的地.

I have 2 coordinates. Coordinate 1 is a 'person'. Coordinate 2 is a destination.

如何将坐标 1 100 米移近坐标 2?

How do I move coordinate 1 100 meters closer to coordinate 2?

这将用于 cron 作业，因此仅包括 php 和 mysql.

This would be used in a cron job, so only php and mysql included.

例如:

联系人在:51.26667, 3.45417

Person is at: 51.26667, 3.45417

目的地是:51.575001, 4.83889

Destination is: 51.575001, 4.83889

我将如何计算距离 Person 更近 100 米的新坐标?

How would i calculate the new coordinates for Person to be 100 meters closer?

推荐答案

使用Haversine计算两点之间的差，以米为单位；然后按比例调整人物坐标的值.

Use Haversine to calculate the difference between the two points in metres; then adjust the value of the person coordinates proportionally.

$radius = 6378100; // radius of earth in meters
$latDist = $lat - $lat2;
$lngDist = $lng - $lng2;
$latDistRad = deg2rad($latDist);
$lngDistRad = deg2rad($lngDist);
$sinLatD = sin($latDistRad);
$sinLngD = sin($lngDistRad);
$cosLat1 = cos(deg2rad($lat));
$cosLat2 = cos(deg2rad($lat2));
$a = ($sinLatD/2)*($sinLatD/2) + $cosLat1*$cosLat2*($sinLngD/2)*($sinLngD/2);
if($a<0) $a = -1*$a;
$c = 2*atan2(sqrt($a), sqrt(1-$a));
$distance = $radius*$c;

培养你的价值观:

$lat = 51.26667;        //  Just South of Aardenburg in Belgium
$lng = 3.45417;
$lat2 = 51.575001;      //  To the East of Breda in Holland
$lng2 = 4.83889;

给出的结果是 102059.82251083 米，102.06 公里

gives a result of 102059.82251083 metres, 102.06 kilometers

调整比例为 100/102059.82251083 = 0.0009798174985988102859004569070625

The ratio to adjust by is 100 / 102059.82251083 = 0.0009798174985988102859004569070625

$newLat = $lat + (($lat2 - $lat) * $ratio);
$newLng = $lng + (($lng2 - $lng) * $ratio);

给出新的纬度 51.266972108109 和经度 3.4555267728867

Gives a new latitude of 51.266972108109 and longitude of 3.4555267728867

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