Putting default value in lt;input type=file....gt;(将默认值放在 lt;input type=file....gt;)
问题描述
<块引用>注意:
答案&下面的评论反映了 2009 年旧浏览器的状态.现在，您实际上可以在 2017 年使用 JavaScript 动态/编程地设置文件输入元素的值.
有关详细信息以及演示，请参阅此问题中的答案:
如何以编程方式设置文件输入值(即:拖放文件时)?
我想更新一个表.因此，当用户想要更新它时，插入表单会出现在默认值出现在输入框中的位置.但我无法加载 <input type=file....>.
代码如下:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><form id="form1" action="details1.php?ar=<?php echo $a;?>&api=<?php echo $ai;?>"method="post" enctype="multipart/form-data"><html xmlns="http://www.w3.org/1999/xhtml"><头><meta http-equiv="Content-Type" content="text/html; charset=utf-8"/><title>欢迎使用 Prime Properties</title><link rel="stylesheet" href="style.css" type="text/css"/><身体><div class="容器"><div class="heading"><div class="banner"><img src="../images/top.jpg" width="995" height="169"/></div><!--菜单开始--><div><?php include('include/menu.php');?><!--菜单结束-->
<div class="main"><!--左侧菜单开始--><div class="left_menu"><?php include('include/lm.php');?>
<!--左侧菜单结束--><div class="divider"></div><!--正文内容在这里--><div class="right"><p> 输入您的凭据......</p><fieldset><p class="first"><label for="a_name" >公寓名称:</label><input type="text" name="a_name" id="a_name" value="<?php echo $an;?>"><br/></input></p><p><label for="b_name">构建器名称:</label><input type="text" name="b_name" id="b_name" value="<?php echo $bn;?>"><br/></input></p><p><label for="loc">位置:</label><select name="loc"><?php $qry1="select location from location where loc_id='$lc'";$result1=mysql_query($qry1) 或 die(mysql_error());while($res = mysql_fetch_array($result1)){$op=$res[0];}?><option value="<?php echo $lc?>"><?php echo $op;?></option><option value="1">Maligaon</option></select><br/></p><p><label for="status">状态:</label><选择名称=状态"><?php $qry1="select status from status where st_id='$st'";$result1=mysql_query($qry1) 或 die(mysql_error());while($res = mysql_fetch_array($result1)){$sts=$res[0];}?><option value="<?php echo $st?>"><?php echo $sts;?></option><option value="1">正在进行中</option><option value="2">未来</option><option value="3">已完成</option></select><br/></p><p><label for="no_flats">公寓数量:</label><input type="text" name="no_flats" id="no_flats" value="<?php echo $nf;?>"><br/></input></p><p><label for="c_time">完成时间:</label><?php $ct1=explode(" ", $ct);?><选择名称=月份"><option><?php echo $ct1[0];?></option><option>一月</option><option>二月</option><option>三月</option></选择><选择名称=年份"><option><?php echo $ct1[1];?></option><option>2012</option><option>2013</option><option>2014</option></选择></p><p><label for="m_pic">主图:</label><td><img src="images/<?php echo $mp?>"width="100" height="70"/></td><input type="file" name="photo"><br/></input></p><p><label for="l_map">位置图:</label><td><img src="loc_images/<?php echo $lm?>"width="100" height="70"/></td><input type="file" name="photo"><br/></input></p><p class="提交"><input type="hidden" name="check" value="1"/><button type="submit" name="submit" >UPDATE</button></p></fieldset></div><!--正文内容在此结束-->
</表单>
我该怎么办?
出于安全原因， 元素的值只能由用户更改.无法通过 JavaScript 或 HTML 更改该值.
Note:
The answers & comments below reflect the state of legacy browsers in 2009. Now you can actually set the value of the file input element dynamically/programatically using JavaScript in 2017.
See the answer in this question for details as well as a demo:
How to set file input value programatically (i.e.: when drag-dropping files)?
I want to update a table. Hence when user wants to update it the insert form appears where the default values appear in the input boxes. But i can't load in the <input type=file....>.
Here is the code:
<?php
session_start();
if(!isset($_SESSION['user']))
{
header("Location:index.php");
exit();
}
include("./include/dbc.php");
$a=$_REQUEST['apt'];
$qry="select * from flats where app_name = '$a'";
$result=mysql_query($qry) or die(mysql_error());
while($res = mysql_fetch_array($result))
{
$ai=$res[0];
$an=$res[1];
$bn=$res[2];
$lc=$res[3];
$st=$res[4];
$nf=$res[5];
$ct=$res[6];
$mp=$res[7];
$lm=$res[8];
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<form id="form1" action="details1.php?ar=<?php echo $a;?>&api=<?php echo $ai;?>" method="post" enctype="multipart/form-data">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Welcome To Prime Properties</title>
<link rel="stylesheet" href="style.css" type="text/css"/>
</head>
<body>
<div class="container">
<div class="heading">
<div class="banner"><img src="../images/top.jpg" width="995" height="169" /></div>
<!--menu start-->
<div>
<?php include('include/menu.php');?>
</div>
<!--menu end-->
</div>
<div class="main">
<!--left menu start-->
<div class="left_menu">
<?php include('include/lm.php');?>
</div>
<!--left menu end-->
<div class="divider"></div>
<!--body contant goes here-->
<div class="right">
<p>
Enter Your Credentials......</p>
<fieldset><p class="first">
<label for="a_name" >Appartment Name:</label>
<input type="text" name="a_name" id="a_name" value="<?php echo $an;?>"><br/></input></p>
<p>
<label for="b_name">Builder Name:</label>
<input type="text" name="b_name" id="b_name" value="<?php echo $bn;?>"><br/></input></p>
<p>
<label for="loc">Location:</label>
<select name="loc">
<?php $qry1="select location from location where loc_id='$lc'";
$result1=mysql_query($qry1) or die(mysql_error());
while($res = mysql_fetch_array($result1)){
$op=$res[0];
}?>
<option value="<?php echo $lc?>"><?php echo $op;?></option>
<option value="1">Maligaon</option>
</select><br/></p>
<p>
<label for="status"> Status:</label>
<select name="status">
<?php $qry1="select status from status where st_id='$st'";
$result1=mysql_query($qry1) or die(mysql_error());
while($res = mysql_fetch_array($result1)){
$sts=$res[0];
}?>
<option value="<?php echo $st?>"><?php echo $sts;?></option>
<option value="1">Ongoing</option>
<option value="2">Future</option>
<option value="3">Completed</option>
</select><br/></p>
<p><label for="no_flats">No of Flats:</label>
<input type="text" name="no_flats" id="no_flats" value="<?php echo $nf;?>"><br/></input></p>
<p><label for="c_time">Completion Time:</label>
<?php $ct1=explode(" ", $ct);
?>
<select name="month">
<option><?php echo $ct1[0];?></option>
<option>January</option>
<option>February</option>
<option>March</option>
</select>
<select name="year">
<option><?php echo $ct1[1];?></option>
<option>2012</option>
<option>2013</option>
<option>2014</option>
</select>
</p>
<p><label for="m_pic">Main Picture:</label>
<td><img src="images/<?php echo $mp?>" width="100" height="70" /></td>
<input type="file" name="photo"><br/></input></p>
<p><label for="l_map">Location Map:</label>
<td><img src="loc_images/<?php echo $lm?>" width="100" height="70" /></td>
<input type="file" name="photo"><br/></input></p>
<p class="submit">
<input type="hidden" name="check" value="1"/>
<button type="submit" name="submit" >UPDATE</button></p>
</fieldset></div>
<!--body contant end here -->
</div>
</body>
</html>
</form>
What i should do?
For security reasons, the value of a <input type=file> element can only be changed by a user. It's not possible to change the value through JavaScript or HTML.
这篇关于将默认值放在 <input type=file....>的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！
本文标题为：将默认值放在 <input type=file....>
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