The sum() function seems to be messing map objects(sum() 函数似乎弄乱了地图对象)
问题描述
我正在做这个代码练习以尝试在 python 中进行函数式编程,但我遇到了 sum()、list() 和 map 对象的问题.我不明白我做错了什么,但 list() 函数似乎与我的地图对象搞砸了.
I'm doing this code excercise for trying out functional programming in python, and I ran into problems with sum(), list(), and map objects. I don't understand what I'm doing wrong, but the list() function seems to be screwing with my map object.
这是我的代码:
people = [{'name': 'Mary', 'height': 160},
{'name': 'Isla', 'height': 80},
{'name': 'Sam'}]
heights = map(lambda x: x['height'], filter(lambda x: 'height' in x, people))
print(len(list(heights)))
print(sum(list(heights)))
print(len(list(heights)))
average_height = sum(list(heights)) / len(list(heights))
print(average_height)
heights 应该是一个地图对象,包含(或产生)两个现有高度条目的列表:[160, 80].
heights should be a map object containing (or resulting in) a list of the two existing height entries: [160, 80].
打印长度应该是2,两者的和显然应该是240,平均应该是120.
printing the length should give 2, the sum of the two should obviously be 240, and the average should be 120.
不过,我面临的问题是我收到以下错误消息:
The problem I'm facing, though, is that I get this error message:
2
0
0
Traceback (most recent call last):
File "C:UsersHugoDropboxProgrammeringPythonProjektexercise2.py", line 12, in <module>
average_height = sum(list(heights)) / len(list(heights))
ZeroDivisionError: division by zero
是的,长度是对的,但是总和是0,第二个长度打印也是0.整个零除错误必须来自那里的某些东西,并且似乎是 list() 函数导致了它.更改打印顺序仍然只能让第一个打印语句正确:
Yes, the length is right, but the sum is 0, and the second length print is 0 aswell. The whole zero-division fault must come from something there, and it seems that the list() function is causing it. Changing the print order still only lets through the first print statement correctly:
print(sum(list(heights)))
print(len(list(heights)))
print(len(list(heights)))
给予:
240
0
0
Traceback (most recent call last):
File "C:UsersHugoDropboxProgrammeringPythonProjektexercise2.py", line 12, in <module>
average_height = sum(list(heights)) / len(list(heights))
ZeroDivisionError: division by zero
并删除 list() 函数:
and removing the list() function:
print(sum(list(heights)))
print(len(heights))
print(len(list(heights)))
给我:
240
Traceback (most recent call last):
File "C:UsersHugoDropboxProgrammeringPythonProjektexercise2.py", line 9, in <module>
print(len(heights))
TypeError: object of type 'map' has no len()
所以我不知道发生了什么.list() 函数不应该以任何方式更改地图对象,对吧?它仍然是一个地图对象,但不止一次调用 list() 似乎会改变它的行为.我很困惑.
So I have no idea what's going on. The list() function should not be changing the map object in any way, right? And it stays a map object, but calling list() on it more than once seems to change its behaviour. I am confuse.
推荐答案
实际上,调用 list
确实会改变你的 map
对象.map
是一个迭代器,而不是一个数据结构(在 Python3 中).在它被循环一次之后,它就被耗尽了.要重现结果,您需要重新创建地图对象.
Actually, calling list
does change your map
object. map
is an iterator, not a data structure (in Python3). After it has been looped over once, it is exhausted. To reproduce the result, you need to recreate the map object.
在您的情况下,您可能想要做的是从地图创建一个列表来存储结果,然后执行 sum
.
In your case, what you probably want to do is create a list from the map to store the result, then perform the sum
.
heights = list(heights)
average = sum(heights) / len(heights)
另一种方法.
您可以使用统计模块直接从迭代器计算算术平均值(和其他统计数据).查看文档.
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本文标题为:sum() 函数似乎弄乱了地图对象
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