查找带有子进程的命令不适用于 Shell=True

find command with subprocess not working with out Shell=True(查找带有子进程的命令不适用于 Shell=True)

问题描述

我的代码中有以下几行.我嵌入了一条短线，用于获取超过 10 分钟的文件列表.我的子流程失败了，几乎没有错误.当我给 Shell=True 时它似乎有效，但我读到使用该选项非常冒险，而且我对 Python 很陌生，不想弄乱我不理解的东西.我曾尝试在 find 语句中和周围更改引号，但这对我没有帮助.您能否建议我如何使用 find 命令获取文件列表.我用这些 find 和 subprocess 组合研究了其他问题，我没有找到任何通配符目录匹配项.我找不到解决方案.

I have below lines in my code. I have embedded a short a line which fetches the list of files that are older than 10 mins. My sub process have been failing with few errors. It seems to work when I give Shell=True, but I read that it is a very risky to use that option and I am very new to the Python, Don't want to mess up with something I am not understanding. I have tried changing quotes with in and around that find statement, but its not helping me. can you please suggest how could I get the list of files using find command. I have looked into other questions with these find and subprocess combinations, I did not find any wildcard directory matches. I could not find solution for this.

cmd = 'find /myapp/uat/aws/6.3/domains/*/appnodes/*/*/log/bwappnode.log -type f -mmin +10'

 apps_in_proc = subprocess.Popen(cmd,stdout=subprocess.PIPE, universal_newlines=True)

推荐答案

如果它与 shell=True 一起工作，并且不是没有，这意味着模式是用 shell=True 扩展的.

if it works with shell=True, and not without, that means that the pattern is expanded with shell=True.

要模拟这种行为，只需使用 glob.glob 并像这样编写命令参数列表:

To emulate this behaviour just use glob.glob and compose your command argument list like this:

cmd = ['find'] + glob.glob('/myapp/uat/aws/6.3/domains/*/appnodes/*/*/log/bwappnode.log') + ['-type','f','-mmin','+10']

在纯python中可以很容易地编写:

Which could be written very easily in pure python:

import glob,os,time
current = time.time()
old_files = [x for x in glob.glob("/myapp/uat/aws/6.3/domains/*/appnodes/*/*/log/bwappnode.log") if current - os.path.getmtime(x) > 600]

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