Python:生成“元组集"；来自“元组列表"；不考虑顺序

我想删除重复的元组(在内容和内部项目的顺序方面重复)，以便输出为:

I would like to remove duplicate tuples (duplicate in terms of both content and order of items inside) so that the output would be:

[('a', 'b'), ('c', 'd')]

或者

[('b', 'a'), ('c', 'd')]

我尝试将其转换为设置然后列表，但输出将同时保持 ('b', 'a') 和 ('a', 'b') 在结果集中！

I tried converting it to set then to list but the output would maintain both ('b', 'a') and ('a', 'b') in the resulting set!

推荐答案

试试这个:

a = [('a', 'b'), ('c', 'd'), ('a', 'b'), ('b', 'a')]
b = list(set([ tuple(sorted(t)) for t in a ]))
[('a', 'b'), ('c', 'd')]

让我们分解一下:

如果你对一个元组进行排序，它就会变成一个排序列表.

If you sort a tuple, it becomes a sorted list.

>>> t = ('b', 'a')
>>> sorted(t)
['a', 'b']

对于 a 中的每个元组 t，对其进行排序并将其转换回元组.

For each tuple t in a, sort it and convert it back to a tuple.

>>> b = [ tuple(sorted(t)) for t in a ]
>>> b
[('a', 'b'), ('c', 'd'), ('a', 'b'), ('a', 'b')]

将结果列表 b 转换为集合:值现在是唯一的.将其转换回列表.

Convert the resulting list b to a set : values are now unique. Convert it back to a list.

>>> list(set(b))
[('a', 'b'), ('c', 'd')]

等等！