pprint sorting dicts but not sets?(pprint 排序字典但不是集合?)
问题描述
我知道 dicts 和 sets 没有顺序,所以相等的 sets 或 dicts 可能会打印不同的内容(所有测试都使用 Python 3.6.1):
>>>对于 {0, 8}, {8, 0}, {0:0, 8:8}, {8:8, 0:0} 中的 obj:打印(对象){0, 8}{8, 0}{0:0, 8:8}{8:8, 0:0}
我刚刚意识到 pprint
(pretty-print") 对 dicts 进行排序,但不对集合进行排序:
>>>对于 {0, 8}, {8, 0}, {0:0, 8:8}, {8:8, 0:0} 中的 obj:pprint.pprint(obj){0, 8}{8, 0}{0:0, 8:8}{0:0, 8:8}
它的文档还说字典在计算显示之前按键排序".但是为什么它也不排序集合呢?在我看来并不漂亮.有没有办法制作排序集?也在嵌套结构中,因为这是 pprint
的主要目的.
这是在 问题中提出的27495,这是一个错误,而不仅仅是一个设计选择,但显然还没有解决.
以下是问题中的另一个示例,它可能更清楚地说明了您在 Python 3 中识别的行为:
<块引用>>>>导入字符串,pprint>>>pprint.pprint(set(string.digits)){'7'、'1'、'9'、'8'、'3'、'0'、'2'、'5'、'6'、'4'}
同样适用于 frozenset()
,但请注意多行 pprint
输出 在 Python 3 中排序,例如:
>>>pprint.pprint(set(string.digits), width=1){'0','1','2','3','4','5','6','7','8','9'}
但是,在 Python 2 中,相同原始代码的输出是排序的:
<块引用>>>>pprint.pprint(set(string.digits))设置(['0','1','2','3','4','5','6','7','8','9'])
我认为是 Python 3 和 Python 2 之间的不一致,以及单行多行行为之间的不一致,导致了这个错误.
对于 dict
s,一个类似的例子说明了输出在 Python 3 或 2 中的排序,因为它应该是:
>>>pprint.pprint({i:None for i in set(string.digits)}){'0':无,1":无,2":无,3":无,4":无,5":无,6":无,7":无,8":无,9":无}
但是,对于 Python 3.6,pprint
对 dict
进行排序可能会令人惊讶,因为它们 已现在订购.但是,由于这只是一个实现细节(目前),我想 pprint
没有义务维护插入顺序(还),这样做会破坏 pprint
始终对 dict
s 进行排序的 Python 版本的自身一致性.
I know that dicts and sets aren't ordered, so equal sets or dicts may print differently (all tests with Python 3.6.1):
>>> for obj in {0, 8}, {8, 0}, {0:0, 8:8}, {8:8, 0:0}:
print(obj)
{0, 8}
{8, 0}
{0: 0, 8: 8}
{8: 8, 0: 0}
And I just realized that pprint
("pretty-print") sorts dicts but not sets:
>>> for obj in {0, 8}, {8, 0}, {0:0, 8:8}, {8:8, 0:0}:
pprint.pprint(obj)
{0, 8}
{8, 0}
{0: 0, 8: 8}
{0: 0, 8: 8}
It's documentation also says "Dictionaries are sorted by key before the display is computed". But why doesn't it also sort sets? Doesn't seem pretty to me. And is there a way to make it sort sets? Also inside nested structures, as that's a main purpose of pprint
.
This was raised in issue 27495 and it is a bug, rather than just a design choice, but apparently has not yet been resolved.
Here is another example from the issue that illustrates perhaps more obviously the behavior you identify in Python 3:
>>> import string, pprint >>> pprint.pprint(set(string.digits)) {'7', '1', '9', '8', '3', '0', '2', '5', '6', '4'}
The same applies for frozenset()
too, but note that multi-line pprint
outputs are sorted in Python 3, for example:
>>> pprint.pprint(set(string.digits), width=1) {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'}
However, in Python 2, the output from the same original code is sorted:
>>> pprint.pprint(set(string.digits)) set(['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'])
I think it is the inconsistency between Python 3 and Python 2, and between the single-line multi-line behavior, that makes this a bug.
For dict
s, a similar example, illustrates as you note, that the output is sorted in either Python 3 or 2, as it should be:
>>> pprint.pprint({i:None for i in set(string.digits)})
{'0': None,
'1': None,
'2': None,
'3': None,
'4': None,
'5': None,
'6': None,
'7': None,
'8': None,
'9': None}
However, for Python 3.6, it could be considered surprising that pprint
sorts dict
s since they are ordered now. However, since this is just an implementation detail (for now) I guess there is no obligation for pprint
to maintain the insertion order (yet), and doing so would break pprint
's own consistency across Python versions of always sorting dict
s.
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