从python中的嵌套字典中获取所有值

沃梦达教程 Python问题

2022-01-01

Get all values from nested dictionaries in python(从python中的嵌套字典中获取所有值)

本文介绍了从python中的嵌套字典中获取所有值的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我有一些字典的字典，像这样:

I have some dictionaries of dictionaries, like this:

a['b']['c']['d']['answer'] = answer1
a['b']['c']['e']['answer'] = answer2
a['b']['c']['f']['answer'] = answer3
....
a['b']['c']['d']['conf'] = conf1
a['b']['c']['e']['conf'] = conf2
a['b']['c']['f']['conf'] = conf3

是否有一种快速的方法可以获取第三级 (d,e,f) 上所有元素的所有答案的值列表?

Is there a fast way to get a list of values of all answers for all elements at the third level (d,e,f)?

特别是我想知道是否有任何实现通配符的机制(例如，a['b']['c']['*']['answer'].values()


Specifically I'd like to know if there's any mechanism implementing a wildcard (e.g., a['b']['c']['*']['answer'].values()
更新到目前为止，我发现的最快方法是:
update
The fastest way I've found till now is:
[x['answer'] for x in a['b']['c'].values()]


推荐答案
只是为了回答这个话题，从我问题的更新状态"复制我的解决方案:
Just to give an answer to this topic, copying my solution from the "updating status" of my question:
[x['answer'] for x in a['b']['c'].values()]

希望能帮到你.

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