Pandas-从具有嵌套列表列表的现有列创建动态列时出错-Python问题

Pandas- Error in creating dynamic columns from existing column having nested list of lists(Pandas-从具有嵌套列表列表的现有列创建动态列时出错)

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问题描述

我要从包含列表嵌套列表作为值的现有列创建两个列。

由3个公司参与者及其角色组成的记录行：

**row 1** [{'roles': [{'type': 'director'}, {'type': 'founder'}, {'type': 'owner'}, {'type': 'real_owner'}], 'life': {'name': 'Lichun Du'}}]

**row 2** [{'roles': [{'type': 'board'}], 'life': {'name': 'Erik Mølgaard'}}, {'roles': [{'type': 'director'}, {'type': 'board'}, {'type': 'real_owner'}], 'life': {'name': 'Mikael Bodholdt Linde'}}, {'roles': [{'type': 'board'}, {'type': 'real_owner'}], 'life': {'name': 'Dorte Bøcker Linde'}}]

**row 3** [{'roles': [{'type': 'director'}, {'type': 'real_owner'}], 'life': {'name': 'Kristian Løth Hougaard'}}, {'roles': [{'type': 'owner'}], 'life': {'name': 'WORLD JET HOLDING ApS'}}]

到目前为止，我已尝试：

    responses['Role of Participant(s)'] = [element[0]['roles'] for element in responses['participants']]
    responses['Role of Participant(s)'] = responses['Role of Participant(s)'].apply(lambda x: ', '.join(t['type'] for t in x))
    responses['Name of Participant(s)'] = [element[0]['life']['name'] for element in responses['participants']]

这给出了以下输出：

它只向我返回第一个参与者的角色和名称

但是，我需要每个行/记录的所有参与者及其各自的角色，如下所示：

那么，如何使用"；*"；作为每个行值的分隔符，如上面的截图所示？ 请帮帮忙！！

更新： 以下是数据帧的CSV版本：

participants
"[{'roles': [{'type': 'founder'}], 'life': {'name': 'Poul Erik Andersen'}}, {'roles': [{'type': 'director'}, {'type': 'board'}], 'life': {'name': 'Martin Ravn-Nielsen'}}, {'roles': [{'type': 'board'}], 'life': {'name': 'Søren Haugaard'}}, {'roles': [{'type': 'board'}], 'life': {'name': 'Mads Dehlsen Winther'}}, {'roles': [{'type': 'founder'}], 'life': {'name': 'M+ Ejendomme A/S'}}, {'roles': [{'type': 'founder'}], 'life': {'name': 'MILTON HOLDING HORSENS A/S'}}, {'roles': [{'type': 'accountant'}], 'life': {'name': 'EY Godkendt Revisionspartnerselskab'}}, {'roles': [{'type': 'owner'}], 'life': {'name': 'HUSCOMPAGNIET HOLDING A/S'}}]"
"[{'roles': [{'type': 'founder'}, {'type': 'director'}, {'type': 'board'}, {'type': 'real_owner'}], 'life': {'name': 'Rasmus Gert Hansen'}}, {'roles': [{'type': 'board'}], 'life': {'name': 'John Nyrup Larsen'}}, {'roles': [{'type': 'board'}], 'life': {'name': 'Ole Nidolf Larsen'}}, {'roles': [{'type': 'owner'}], 'life': {'name': 'RASMUS HANSEN HOLDING ApS'}}, {'roles': [{'type': 'accountant'}], 'life': {'name': 'DANSK REVISION SLAGELSE GODKENDT REVISIONSAKTIESELSKAB'}}]"
"[{'roles': [{'type': 'board'}], 'life': {'name': 'Berit Pedersen'}}, {'roles': [{'type': 'board'}], 'life': {'name': 'Sanne Kristine Späth'}}, {'roles': [{'type': 'real_owner'}], 'life': {'name': 'Kjeld Kirk Kristiansen'}}, {'roles': [{'type': 'director'}], 'life': {'name': 'Jesper Andersen'}}, {'roles': [{'type': 'board'}], 'life': {'name': 'Poul Hartvig Nielsen'}}, {'roles': [{'type': 'board'}], 'life': {'name': 'Nanna Birgitta Gudum'}}, {'roles': [{'type': 'board'}], 'life': {'name': 'Henrik Baagøe Fredeløkke'}}, {'roles': [{'type': 'board'}], 'life': {'name': 'Carsten Rasmussen'}}, {'roles': [{'type': 'board'}], 'life': {'name': 'Jesper Laursen'}}, {'roles': [{'type': 'board'}], 'life': {'name': 'John Hansen'}}, {'roles': [{'type': 'owner'}], 'life': {'name': 'LEGO A/S'}}, {'roles': [{'type': 'accountant'}], 'life': {'name': 'PRICEWATERHOUSECOOPERS STATSAUTORISERET REVISIONSPARTNERSELSKAB'}}]"

推荐答案

您需要第二个for循环，而不是[0]

我使用普通函数而不是lambda以使其更具可读性。

第一个角色：

import pandas as pd

data = {'participants': 
[
    [{'roles': [{'type': 'director'}, {'type': 'founder'}, {'type': 'owner'}, {'type': 'real_owner'}], 'life': {'name': 'Lichun Du'}}],
    [{'roles': [{'type': 'board'}], 'life': {'name': 'Erik Mølgaard'}}, {'roles': [{'type': 'director'}, {'type': 'board'}, {'type': 'real_owner'}], 'life': {'name': 'Mikael Bodholdt Linde'}}, {'roles': [{'type': 'board'}, {'type': 'real_owner'}], 'life': {'name': 'Dorte Bøcker Linde'}}],
    [{'roles': [{'type': 'director'}, {'type': 'real_owner'}], 'life': {'name': 'Kristian Løth Hougaard'}}, {'roles': [{'type': 'owner'}], 'life': {'name': 'WORLD JET HOLDING ApS'}}],
]
}

df = pd.DataFrame(data)

def get_roles(cell):
    
    results = []
    
    for item in cell:
        roles = []
        for role in item['roles']:
            roles.append(role['type'])
        results.append(",".join(roles))
    
    results = "***".join(results)

    return results

df['Role of Participant(s)'] = df['participants'].apply(get_roles)

print(df[['Role of Participant(s)']].to_string())

结果：

                                 Role of Participant(s)
0                     director,founder,owner,real_owner
1  board***director,board,real_owner***board,real_owner
2                           director,real_owner***owner

现在您可以尝试写为lambda

df['Role of Participant(s)'] = df['participants'].apply(lambda cell:"***".join([",".join(role['type'] for role in item['roles']) for item in cell]))

类似名称：

def get_names(cell):
    
    results = []
    
    for item in cell:
        results.append(item['life']['name'])
    
    results = "***".join(results)

    return results

df['Name of Participant(s)'] = df['participants'].apply(get_names)

和现在的lambda

df['Name of Participant(s)'] = df['participants'].apply(lambda cell:"***".join(item['life']['name'] for item in cell))

编辑：

在一个apply中创建两列并跳过具有director角色的参与者的版本

import pandas as pd

data = {'participants': 
[
    [{'roles': [{'type': 'director'}, {'type': 'founder'}, {'type': 'owner'}, {'type': 'real_owner'}], 'life': {'name': 'Lichun Du'}}],
    [{'roles': [{'type': 'board'}], 'life': {'name': 'Erik Mølgaard'}}, {'roles': [{'type': 'director'}, {'type': 'board'}, {'type': 'real_owner'}], 'life': {'name': 'Mikael Bodholdt Linde'}}, {'roles': [{'type': 'board'}, {'type': 'real_owner'}], 'life': {'name': 'Dorte Bøcker Linde'}}],
    [{'roles': [{'type': 'director'}, {'type': 'real_owner'}], 'life': {'name': 'Kristian Løth Hougaard'}}, {'roles': [{'type': 'owner'}], 'life': {'name': 'WORLD JET HOLDING ApS'}}],
]
}

df = pd.DataFrame(data)

def get_names_and_roles(cell):
    
    all_names = []
    all_roles = []
    
    for item in cell:
        name = item['life']['name']
        roles = [role['type'] for role in item['roles']]

        if 'director' not in roles:
            all_names.append(name)
            all_roles.append(",".join(roles))
    
    all_names = "***".join(all_names)
    all_roles = "***".join(all_roles)

    return pd.Series([all_names, all_roles])


df[ ['Name of Participant(s)', 'Role of Participant(s)'] ] = df['participants'].apply(get_names_and_roles)

print(df[ ['Name of Participant(s)', 'Role of Participant(s)'] ].to_string())

结果：

               Name of Participant(s)    Role of Participant(s)
0                                                              
1  Erik Mølgaard***Dorte Bøcker Linde  board***board,real_owner
2               WORLD JET HOLDING ApS                     owner

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