PyQt - how to detect and close UI if it#39;s already running?(PyQt - 如果 UI 已经在运行,如何检测并关闭它?)
问题描述
我从 Maya 中启动 UI.如果 UI 尚未关闭,再次运行 UI 将完全冻结 Maya(出现错误事件循环已在运行")
I'm starting the UI from within Maya. If the UI hasn't been closed, running the UI again will completely freeze Maya (with the error "Event Loop is already running")
在重新运行脚本之前手动关闭 UI 将防止它冻结.但我想这不太实用.
Manually closing the UI before re-running the script will prevent it from freezing up. But I guess that's not really practical.
有没有办法检测我尝试运行的 UI 是否已经存在?并可能强制关闭它?
Is there a way to detect if the UI I'm trying to run already exists? And possible force close it?
推荐答案
这是一个非常简单的 PyQt5 解决方案,使用 QLockFile:
Here is a very simple PyQt5 solution using QLockFile:
from PyQt5 import QtCore, QtWidgets
lockfile = QtCore.QLockFile(QtCore.QDir.tempPath() + '/my_app_name.lock')
if lockfile.tryLock(100):
app = QtWidgets.QApplication([])
win = QtWidgets.QWidget()
win.setGeometry(50, 50, 100, 100)
win.show()
app.exec()
else:
print('app is already running')
<小时>
Qt Wiki 上提供了几个相当简单的 C++ 解决方案,但它们似乎不再存在.我将其中一个移植到 PyQt,并在下面提供了一个示例脚本.最初的 C++ 解决方案已被分为两类,因为可能不需要消息传递工具.
There were a couple of fairly straightforward C++ solutions given on the Qt Wiki which no longer seem to exist. I ported one of them to PyQt, and have provided a sample script below. The original C++ solution has been split into two classes, because the messaging facility may not be needed.
PyQt5:
from PyQt5 import QtWidgets, QtCore, QtNetwork
class SingleApplication(QtWidgets.QApplication):
messageAvailable = QtCore.pyqtSignal(object)
def __init__(self, argv, key):
super().__init__(argv)
# cleanup (only needed for unix)
QtCore.QSharedMemory(key).attach()
self._memory = QtCore.QSharedMemory(self)
self._memory.setKey(key)
if self._memory.attach():
self._running = True
else:
self._running = False
if not self._memory.create(1):
raise RuntimeError(self._memory.errorString())
def isRunning(self):
return self._running
class SingleApplicationWithMessaging(SingleApplication):
def __init__(self, argv, key):
super().__init__(argv, key)
self._key = key
self._timeout = 1000
self._server = QtNetwork.QLocalServer(self)
if not self.isRunning():
self._server.newConnection.connect(self.handleMessage)
self._server.listen(self._key)
def handleMessage(self):
socket = self._server.nextPendingConnection()
if socket.waitForReadyRead(self._timeout):
self.messageAvailable.emit(
socket.readAll().data().decode('utf-8'))
socket.disconnectFromServer()
else:
QtCore.qDebug(socket.errorString())
def sendMessage(self, message):
if self.isRunning():
socket = QtNetwork.QLocalSocket(self)
socket.connectToServer(self._key, QtCore.QIODevice.WriteOnly)
if not socket.waitForConnected(self._timeout):
print(socket.errorString())
return False
if not isinstance(message, bytes):
message = message.encode('utf-8')
socket.write(message)
if not socket.waitForBytesWritten(self._timeout):
print(socket.errorString())
return False
socket.disconnectFromServer()
return True
return False
class Window(QtWidgets.QWidget):
def __init__(self):
super().__init__()
self.edit = QtWidgets.QLineEdit(self)
self.edit.setMinimumWidth(300)
layout = QtWidgets.QVBoxLayout(self)
layout.addWidget(self.edit)
def handleMessage(self, message):
self.edit.setText(message)
if __name__ == '__main__':
import sys
key = 'app-name'
# send commandline args as message
if len(sys.argv) > 1:
app = SingleApplicationWithMessaging(sys.argv, key)
if app.isRunning():
print('app is already running')
app.sendMessage(' '.join(sys.argv[1:]))
sys.exit(1)
else:
app = SingleApplication(sys.argv, key)
if app.isRunning():
print('app is already running')
sys.exit(1)
window = Window()
app.messageAvailable.connect(window.handleMessage)
window.show()
sys.exit(app.exec_())
PyQt4:
# only needed for python2
import sip
sip.setapi('QString', 2)
from PyQt4 import QtGui, QtCore, QtNetwork
class SingleApplication(QtGui.QApplication):
messageAvailable = QtCore.pyqtSignal(object)
def __init__(self, argv, key):
QtGui.QApplication.__init__(self, argv)
# cleanup (only needed for unix)
QtCore.QSharedMemory(key).attach()
self._memory = QtCore.QSharedMemory(self)
self._memory.setKey(key)
if self._memory.attach():
self._running = True
else:
self._running = False
if not self._memory.create(1):
raise RuntimeError(self._memory.errorString())
def isRunning(self):
return self._running
class SingleApplicationWithMessaging(SingleApplication):
def __init__(self, argv, key):
SingleApplication.__init__(self, argv, key)
self._key = key
self._timeout = 1000
self._server = QtNetwork.QLocalServer(self)
if not self.isRunning():
self._server.newConnection.connect(self.handleMessage)
self._server.listen(self._key)
def handleMessage(self):
socket = self._server.nextPendingConnection()
if socket.waitForReadyRead(self._timeout):
self.messageAvailable.emit(
socket.readAll().data().decode('utf-8'))
socket.disconnectFromServer()
else:
QtCore.qDebug(socket.errorString())
def sendMessage(self, message):
if self.isRunning():
socket = QtNetwork.QLocalSocket(self)
socket.connectToServer(self._key, QtCore.QIODevice.WriteOnly)
if not socket.waitForConnected(self._timeout):
print(socket.errorString())
return False
if not isinstance(message, bytes):
message = message.encode('utf-8')
socket.write(message)
if not socket.waitForBytesWritten(self._timeout):
print(socket.errorString())
return False
socket.disconnectFromServer()
return True
return False
class Window(QtGui.QWidget):
def __init__(self):
QtGui.QWidget.__init__(self)
self.edit = QtGui.QLineEdit(self)
self.edit.setMinimumWidth(300)
layout = QtGui.QVBoxLayout(self)
layout.addWidget(self.edit)
def handleMessage(self, message):
self.edit.setText(message)
if __name__ == '__main__':
import sys
key = 'app-name'
# send commandline args as message
if len(sys.argv) > 1:
app = SingleApplicationWithMessaging(sys.argv, key)
if app.isRunning():
print('app is already running')
app.sendMessage(' '.join(sys.argv[1:]))
sys.exit(1)
else:
app = SingleApplication(sys.argv, key)
if app.isRunning():
print('app is already running')
sys.exit(1)
window = Window()
app.messageAvailable.connect(window.handleMessage)
window.show()
sys.exit(app.exec_())
这篇关于PyQt - 如果 UI 已经在运行,如何检测并关闭它?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:PyQt - 如果 UI 已经在运行,如何检测并关闭它?


基础教程推荐
- 无法导入 Pytorch [WinError 126] 找不到指定的模块 2022-01-01
- PermissionError: pip 从 8.1.1 升级到 8.1.2 2022-01-01
- 在Python中从Azure BLOB存储中读取文件 2022-01-01
- 修改列表中的数据帧不起作用 2022-01-01
- 使用大型矩阵时禁止 Pycharm 输出中的自动换行符 2022-01-01
- 在同一图形上绘制Bokeh的烛台和音量条 2022-01-01
- PANDA VALUE_COUNTS包含GROUP BY之前的所有值 2022-01-01
- 包装空间模型 2022-01-01
- 求两个直方图的卷积 2022-01-01
- Plotly:如何设置绘图图形的样式,使其不显示缺失日期的间隙? 2022-01-01