Jasmine JavaScript Testing - toBe vs toEqual(Jasmine JavaScript 测试 - toBe vs toEqual)
问题描述
假设我有以下内容:
var myNumber = 5;期望(myNumber).toBe(5);期望(myNumber).toEqual(5);
以上两个测试都将通过.toBe() 和
toEqual()
在计算数字时有区别吗?如果是这样,我什么时候应该使用一个而不是另一个?
对于原始类型(例如数字、布尔值、字符串等),toBe
和toEqual没有区别
;任何一个都适用于 5
、true
或 "the cake is a lie"
.
为了理解 toBe
和 toEqual
之间的区别,让我们想象三个对象.
var a = { bar: 'baz' },b = { foo: a },c = { foo: a };
使用严格比较(===
),有些东西是相同的":
<代码>>b.foo.bar === c.foo.bar真的>b.foo.bar === a.bar真的>c.foo === b.foo真的
但是有些东西,即使它们相等",也不是相同的",因为它们代表了存在于内存中不同位置的对象.
<代码>>b === c错误的
Jasmine 的 toBe
匹配器只不过是严格相等比较的包装器
expect(c.foo).toBe(b.foo)
和
是一样的expect(c.foo === b.foo).toBe(true)
不要只相信我的话;参见toBe的源代码.p>
但是b
和c
代表功能上等价的对象;他们都长得像
{ foo: { bar: 'baz' } }
如果我们可以说 b
和 c
是相等的",那不是很好吗?即使它们不代表同一个对象?
输入 toEqual
,它检查深度相等";(即对对象进行递归搜索以确定其键的值是否相等).以下两项测试都将通过:
expect(b).not.toBe(c);期望(b).toEqual(c);
希望这有助于澄清一些事情.
Let's say I have the following:
var myNumber = 5;
expect(myNumber).toBe(5);
expect(myNumber).toEqual(5);
Both of the above tests will pass. Is there a difference between toBe()
and toEqual()
when it comes to evaluating numbers? If so, when I should use one and not the other?
For primitive types (e.g. numbers, booleans, strings, etc.), there is no difference between toBe
and toEqual
; either one will work for 5
, true
, or "the cake is a lie"
.
To understand the difference between toBe
and toEqual
, let's imagine three objects.
var a = { bar: 'baz' },
b = { foo: a },
c = { foo: a };
Using a strict comparison (===
), some things are "the same":
> b.foo.bar === c.foo.bar
true
> b.foo.bar === a.bar
true
> c.foo === b.foo
true
But some things, even though they are "equal", are not "the same", since they represent objects that live in different locations in memory.
> b === c
false
Jasmine's toBe
matcher is nothing more than a wrapper for a strict equality comparison
expect(c.foo).toBe(b.foo)
is the same thing as
expect(c.foo === b.foo).toBe(true)
Don't just take my word for it; see the source code for toBe.
But b
and c
represent functionally equivalent objects; they both look like
{ foo: { bar: 'baz' } }
Wouldn't it be great if we could say that b
and c
are "equal" even if they don't represent the same object?
Enter toEqual
, which checks "deep equality" (i.e. does a recursive search through the objects to determine whether the values for their keys are equivalent). Both of the following tests will pass:
expect(b).not.toBe(c);
expect(b).toEqual(c);
Hope that helps clarify some things.
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