Uncaught TypeError: this.method is not a function - Node js class export(未捕获的类型错误:this.method 不是函数 - 节点 js 类导出)
问题描述
我是 node.js 的新手,我正在尝试要求一个类.我用过 https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Classes 作为参考.但是,例如,当我这样做时:
I am new to node.js and I am trying to require a class. I have used https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Classes as reference. However, when I do this for example:
// talker.js
class Talker {
talk(msg) {
console.log(this.say(msg))
var t = setTimeout(this.talk, 5000, 'hello again');
}
say(msg) {
return msg
}
}
export default Talker
// app.js
import Talker from './taker.js'
const talker = new Talker()
talker.talk('hello')
我明白了:
talker.js:4 Uncaught TypeError: this.say 不是函数
talker.js:4 Uncaught TypeError: this.say is not a function
应该说app.js是electron.js的渲染进程,使用rollup.js捆绑
It should be said that app.js is the electron.js renderer process and it bundled using rollup.js
任何想法为什么会这样?
Any ideas why this would be?
更新:抱歉,我在输入伪代码时忘记添加一行.当我用回调调用 setTimeout
时,它实际上会发生.我已经更新了代码.
Update: Sorry, I forgot to add in a line when putting in the psuedo code. It actually happens when I call setTimeout
with callback. I have updated the code.
推荐答案
你正在失去 this
对你的方法的绑定.
You are losing the bind of this
to your method.
从此改变:
setTimeout(this.talk, 5000, 'hello again');
到这里:
setTimeout(this.talk.bind(this), 5000, 'hello again');
<小时>
当您将 this.talk
作为函数参数传递时,它接受 this
并查找方法 talk
并传递对该方法的引用功能.但是,它只传递对该函数的引用.与您在 this
中的对象不再有任何关联..bind()
允许您将引用传递给一个小存根函数,该函数将跟踪 this
并将您的方法称为 this.say()
,而不仅仅是 say()
.
When you pass this.talk
as a function argument, it takes this
and looks up the method talk
and passes a reference to that function. But, it only passes a reference to that function. There is no longer any association with the object you had in this
. .bind()
allows you to pass a reference to a tiny stub function that will keep track of this
and call your method as this.say()
, not just as say()
.
如果你这样做,你会看到同样的事情:
You can see the same thing if you just did this:
const talker = new Talker();'
const fn = talker.say;
fn();
这会产生同样的问题,因为将方法分配给 fn
根本不会与 talker
关联.它只是一个函数引用,与对象没有任何关联.事实上:
This would generate the same issue because assigning the method to fn
takes no associate to talker
with it at all. It's just a function reference without any association with an object. In fact:
talker.say === Talker.prototype.say
.bind()
所做的是创建一个小的存根函数,该函数将保存对象值,然后使用该对象调用您的方法.
What .bind()
does is create a small stub function that will save the object value and will then call your method using that object.
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