如何从 Javascript 函数将参数传递给 XSLT

2023-01-29前端开发问题

本文介绍了如何从 Javascript 函数将参数传递给 XSLT的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着跟版网的小编来一起学习吧！

问题描述

我浏览了许多试图解释如何实现这一目标的帖子，但是没有一个可以帮助我解决问题.

I have scoured through numerous posts that try and explain how to achieve this, however none have helped me solve the problem.

我有一个 HTML 文件，其中包含一个 XML 解析 JavaScript 函数，该函数依次呈现 XSLT 文件.问题是，我的 XML 文件中有多个记录"，我只想要一个 XSLT 来呈现每条记录(而不是每条记录一个单独的 XSLT 文件).根据下面的代码，请有人建议我如何从 JavaScript 传递一个包含记录 id 的参数(在我的 XML 文件中的每个 XML 记录中)，以便单个"XSLT 可以使用来自的正确数据解析布局参数.

I have a HTML file which contains an XML parsing JavaScript function which in turn renders the XSLT file. The issue is, I have multiple 'records' in my XML file and I only want a single XSLT to render each of records (instead of a separate XSLT file per record). Based on the code below, please could someone advise on how I can pass a parameter from JavaScript containing the record id (in each XML record in my XML file) so that the 'single' XSLT can parse the layout with the correct data sourced from the parameter.

HTML

<!DOCTYPE html>
    <html lang="en">
    <head>
      <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
      <meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1.0, user-scalable=no" />
      <title>Weather App</title>

      <link href="../../css/materialize.css" type="text/css" rel="stylesheet" media="screen,projection" />
      <link href="../../css/animate.css" type="text/css" rel="stylesheet" />
      <link href="../../css/style.css" type="text/css" rel="stylesheet" media="screen,projection" />
    </head>

    <body>

      <div id="WeatherDetailsContainer"></div>

      <!--  Scripts-->
      <script src="https://code.jquery.com/jquery-2.1.1.min.js"></script>
      <script src="../../js/materialize.js"></script>

      <script>

        $(function(){
          RenderXSLT();
        });

        function loadXMLDoc(filename) {
          if (window.ActiveXObject) {
            xhttp = new ActiveXObject("Msxml2.XMLHTTP");
          } else {
            xhttp = new XMLHttpRequest();
          }
          xhttp.open("GET", filename, false);
          try {
            xhttp.responseType = "msxml-document"
          } catch (err) {} // Helping IE11
          xhttp.send("");
          return xhttp.responseXML;
        }

        function RenderXSLT() {
          xml = loadXMLDoc("datastore/Weather.xml");
          xslt = loadXMLDoc("transformations/WeatherDetailsCard.xslt");
          var currentLocation = localStorage.getItem('current_weather_location');

          if (window.ActiveXObject || xhttp.responseType == "msxml-document") {
            ex = xml.transformNode(xslt);
            document.getElementById("WeatherDetailsContainer").innerHTML = ex;
          }
          else if (document.implementation && document.implementation.createDocument) {
            xsltProcessor = new XSLTProcessor();
            xsltProcessor.importStylesheet(xslt);

            /** I believe this is how to set the param, but it didn't work **/
            //xsltProcessor.setParameter(null, "cityname", currentLocation);

            resultDocument = xsltProcessor.transformToFragment(xml, document);
            document.getElementById("WeatherDetailsContainer").appendChild(resultDocument);
          }
        }
      </script>

    </body>
    </html>

XML 文件

<?xml version="1.0" encoding="UTF-8" ?>
<locations>

  <location>
    <cityid>Lon</cityid>
    <cityname>London</cityname>
    <temperature>11</temperature>
    <high>13</high>
    <low>4</low>
    <date>17/03/2015</date>
  </location>

  <location>
    <cityid>Man</cityid>
    <cityname>Manchester</cityname>
    <temperature>07</temperature>
    <high>08</high>
    <low>2</low>
    <date>17/03/2015</date>
  </location>

  <location>
    <cityid>Gla</cityid>
    <cityname>Glasgow</cityname>
    <temperature>05</temperature>
    <high>06</high>
    <low>1</low>
    <date>17/03/2015</date>
  </location>

</locations>

XSLT 文件

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">

    <!-- How do I use the value of the parameter sent via JavaScript for the cityname (in place of value 'London') -->
    <xsl:for-each select="locations/location[cityname='London']">

      <div class="section">
        <div class="container">
          <div class="row">
            <div class="col s4 m4 l4">
              <div class="card-panel z-depth-3 animated fadeInUp" style="padding:10px 10px 5px 10px !important;">
                <span class="center-align">
                  <h5><xsl:value-of select="cityname"/></h5><span> (<xsl:value-of select="cityid"/>)</span>
                </span>
                <p>Temp: <xsl:value-of select="temperature"/></p>
                <p>High: <xsl:value-of select="high"/></p>
                <p>Low: <xsl:value-of select="low"/></p>                
              </div>
            </div>
          </div>
        </div>
      </div>

    </xsl:for-each>

</xsl:template>
</xsl:stylesheet>

推荐答案

在XSLT中你需要改变

In the XSLT you need to change

<xsl:template match="/">

    <!-- How do I use the value of the parameter sent via JavaScript for the cityname (in place of value 'London') -->
    <xsl:for-each select="locations/location[cityname='London']">

到

<xsl:param name="cityname"/>

<xsl:template match="/">

    <!-- How do I use the value of the parameter sent via JavaScript for the cityname (in place of value 'London') -->
    <xsl:for-each select="locations/location[cityname = $cityname]">

我还会设置 <xsl:output method="html"/> 因为您只是创建 HTML 片段，而 XSLT 处理器不知道如果您不设置输出方法.

I would also set <xsl:output method="html"/> as you are only creating a fragment of HTML and the XSLT processor does not know that if you don't set the output method.

在您的 Mozilla、Chrome、Opera 的 Javascript 代码中，我会更改检查

In your Javascript code for Mozilla, Chrome, Opera I would change the check

      else if (document.implementation && document.implementation.createDocument) {
        xsltProcessor = new XSLTProcessor();
        xsltProcessor.importStylesheet(xslt);

        /** I believe this is how to set the param, but it didn't work **/
        //xsltProcessor.setParameter(null, "cityname", currentLocation);

        resultDocument = xsltProcessor.transformToFragment(xml, document);
        document.getElementById("WeatherDetailsContainer").appendChild(resultDocument);
      }

到

      else if (typeof XSLTProcessor !== 'undefined') {
        var xsltProcessor = new XSLTProcessor();
        xsltProcessor.importStylesheet(xslt);


        xsltProcessor.setParameter(null, "cityname", currentLocation);

        var resultFragment = xsltProcessor.transformToFragment(xml, document);
        document.getElementById("WeatherDetailsContainer").appendChild(resultFragment);
      }

你的 IE 代码 transformNode 不允许设置参数，你也需要改变那部分，改变

Your IE code with transformNode does not allow to set parameters, you will need to change that part as well, change

      if (window.ActiveXObject || xhttp.responseType == "msxml-document") {
        ex = xml.transformNode(xslt);
        document.getElementById("WeatherDetailsContainer").innerHTML = ex;
      }

到

      if (window.ActiveXObject || xhttp.responseType == "msxml-document") {
        var template = new ActiveXObject('Msxml2.XslTemplate');
        template.stylesheet = xslt;
        var proc = template.createProcessor();
        proc.input = xml;
        proc.addParameter('cityname', currentLocation);
        proc.transform();
        document.getElementById("WeatherDetailsContainer").innerHTML = proc.output;
      }

这篇关于如何从 Javascript 函数将参数传递给 XSLT的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持跟版网！

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