leaflet square given centre and square width(传单正方形给定中心和正方形宽度)
问题描述
在 Leaflet 上,给定中心和半径,我可以轻松创建一个新圆:
On Leaflet I can create a new circle easily given the centre and the radius:
// Circle
var radius = 500; // [metres]
var circleLocation = new L.LatLng(centreLat, centreLon);
var circleOptions = {
color: 'red',
fillColor: '#f03',
fillOpacity: 0.5
};
var circle = new L.Circle(circleLocation, radius, circleOptions);
map.addLayer(circle);
上面的圆圈创建和绘制没有问题,所以就是这样.
The circle above is created and drawn without problems, so it is all.
但是,如果我现在想创建并绘制一个与圆为界的矩形,它就行不通了.这是我所做的:
However, if I wanted now to create and draw a rectangle that which bounds the circle, it does not work. Here is what I did:
// Rectangle
var halfside = radius; // It was 500 metres as reported above
// convert from latlng to a point (<-- I think the problem is here!)
var centre_point = map.latLngToContainerPoint([newCentreLat, newCentreLon]);
// Compute SouthWest and NorthEast points
var sw_point = L.point([centre_point.x - halfside, centre_point.y - halfside]);
var ne_point = L.point([centre_point.x + halfside, centre_point.y + halfside]);
// Convert the obtained points to latlng
var sw_LatLng = map.containerPointToLatLng(sw_point);
var ne_LatLng = map.containerPointToLatLng(ne_point);
// Create bound
var bounds = [sw_LatLng, ne_LatLng];
var rectangleOptions = {
color: 'red',
fillColor: '#f03',
fillOpacity: 0.5
};
var rectangle = L.rectangle(bounds, rectangleOptions);
map.addLayer(rectangle);
我得到的矩形的大小与500米无关.此外,看起来矩形的大小取决于地图的缩放级别.圈子没有出现这些问题.
The size of the rectangle that I obtain has nothing to do with 500 metres. Also, it looks like the size of the rectangle depends on the zoom level the map is. None of these problems arose for the circle.
我怀疑我将纬度/经度转换为点的方式是错误的,反之亦然.
I suspect the way I transform the latitude/longitude to point and viceversa is wrong.
推荐答案
使用L.Circle
继承自L.Path
getBounds方法即可代码>:
Just use the getBounds
method that L.Circle
inherits from L.Path
:
返回路径的 LatLngBounds.
Returns the LatLngBounds of the path.
http://leafletjs.com/reference.html#path-getbounds
var circle = new L.Circle([0,0], 500).addTo(map);
var rectangle = new L.Rectangle(circle.getBounds()).addTo(map);
Plunker 上的工作示例:http://plnkr.co/edit/n55xLOIohNMY6sVA3GLT?p=preview
Working example on Plunker: http://plnkr.co/edit/n55xLOIohNMY6sVA3GLT?p=preview
这篇关于传单正方形给定中心和正方形宽度的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:传单正方形给定中心和正方形宽度
基础教程推荐
- Electron 将 Node.js 和 Chromium 上下文结合起来意味着 2022-01-01
- 用于 Twitter 小部件宽度的 HTML/CSS 2022-01-01
- html表格如何通过更改悬停边框来突出显示列? 2022-01-01
- 直接将值设置为滑块 2022-01-01
- Chart.js 在线性图表上拖动点 2022-01-01
- Vue 3 – <过渡>渲染不能动画的非元素根节点 2022-01-01
- 自定义 XMLHttpRequest.prototype.open 2022-01-01
- 我可以在浏览器中与Babel一起使用ES模块,而不捆绑我的代码吗? 2022-01-01
- 如何使用JIT在顺风css中使用布局变体? 2022-01-01
- 如何使用TypeScrip将固定承诺数组中的项设置为可选 2022-01-01