How to sort a array of object based on two properties and check the rage is sequential?(如何根据两个属性对对象数组进行排序,并检查范围是否连续?)
本文介绍了如何根据两个属性对对象数组进行排序,并检查范围是否连续?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个对象数组,其中的值具有范围,我希望根据范围对值进行排序。首先,它应该基于ConditionalTo进行排序,然后在Conditional From to ConditionalTo范围内,它应该对cultationTo进行排序。 数组
[
{conditionalFrom: 0, conditionalTo: 10000, computationFrom: 0, computationTo: 1000},
{conditionalFrom: 10001, conditionalTo: 10000000, computationFrom: 1001, computationTo: 100000},
{conditionalFrom: 10001, conditionalTo: 999999999999, computationFrom: 0, computationTo: 1000}
]
预期结果
[
{conditionalFrom: 0, conditionalTo: 10000, computationFrom: 0, computationTo: 1000},
{conditionalFrom: 10001, conditionalTo: 999999999999, computationFrom: 0, computationTo: 1000},
{conditionalFrom: 10001, conditionalTo: 10000000, computationFrom: 1001, computationTo: 100000},
]
数组
[
{conditionalFrom: 10001, conditionalTo: 10000000, computationFrom: 1001, computationTo: 100000},
{conditionalFrom: 0, conditionalTo: 10000, computationFrom: 1001, computationTo: 100000},
{conditionalFrom: 0, conditionalTo: 10000, computationFrom: 0, computationTo: 1000},
{conditionalFrom: 10001, conditionalTo: 10000000, computationFrom: 0, computationTo: 1000},
]
预期结果
[
{conditionalFrom: 0, conditionalTo: 10000, computationFrom: 0, computationTo: 1000},
{conditionalFrom: 0, conditionalTo: 10000, computationFrom: 1001, computationTo: 100000},
{conditionalFrom: 10001, conditionalTo: 10000000, computationFrom: 0, computationTo: 1000},
{conditionalFrom: 10001, conditionalTo: 10000000, computationFrom: 1001, computationTo: 100000}
]
在两种情况下使用loaash但输出都不正确
const SlabDetails = orderBy(this.tableData, [r => r.conditionalTo - r.conditionalFrom, r => r.computationTo - r.computationFrom], "asc");
推荐答案
您可以使用_.sortBy
指定wnated属性。
const
sort = data => _.sortBy(data, [
'conditionalFrom',
'computationFrom',
'computationTo'
]),
data0 = [{ conditionalFrom: 0, conditionalTo: 10000, computationFrom: 0, computationTo: 1000 }, { conditionalFrom: 10001, conditionalTo: 10000000, computationFrom: 1001, computationTo: 100000 }, { conditionalFrom: 10001, conditionalTo: 999999999999, computationFrom: 0, computationTo: 1000 }],
data1 = [{ conditionalFrom: 0, conditionalTo: 10000, computationFrom: 0, computationTo: 1000 }, { conditionalFrom: 0, conditionalTo: 10000, computationFrom: 1001, computationTo: 100000 }, { conditionalFrom: 10001, conditionalTo: 10000000, computationFrom: 0, computationTo: 1000 }, { conditionalFrom: 10001, conditionalTo: 10000000, computationFrom: 1001, computationTo: 100000 }];
console.log(sort(data0));
console.log(sort(data1));
.as-console-wrapper { max-height: 100% !important; top: 0; }
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.15/lodash.min.js"></script>
这篇关于如何根据两个属性对对象数组进行排序,并检查范围是否连续?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
沃梦达教程
本文标题为:如何根据两个属性对对象数组进行排序,并检查范围是否连续?
基础教程推荐
猜你喜欢
- 在 JS 中获取客户端时区(不是 GMT 偏移量) 2022-01-01
- 我什么时候应该在导入时使用方括号 2022-01-01
- 在for循环中使用setTimeout 2022-01-01
- 响应更改 div 大小保持纵横比 2022-01-01
- 有没有办法使用OpenLayers更改OpenStreetMap中某些要素 2022-09-06
- Karma-Jasmine:如何正确监视 Modal? 2022-01-01
- 动态更新多个选择框 2022-01-01
- 当用户滚动离开时如何暂停 youtube 嵌入 2022-01-01
- 角度Apollo设置WatchQuery结果为可用变量 2022-01-01
- 悬停时滑动输入并停留几秒钟 2022-01-01