c# 使用WebRequest实现多文件上传-C#/.NET开发

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添加引用

使用WebRequest需要添加引用System.Web,否则引入出错。

参数封装

方便起见，我把请求参数进行了封装，代码如下:


namespace EasyHttp.Net.Core
{
  public class KeyValue
  {
    public string Key;
    public string Value;
    public string FilePath;
    public string ContentType="*/*";

    public KeyValue(string key, string value, string filePath, string contentType)
    {
      Key = key;
      Value = value;
      FilePath = filePath;
      ContentType = contentType;
    }

    public KeyValue() { }

    public KeyValue(string key, string value, string filePath)
    {
      Key = key;
      Value = value;
      FilePath = filePath;
    }

    public KeyValue(string key, string value)
    {
      Key = key;
      Value = value;
    }
  }
}

KeyValue代表了广义的参数，可以是普通的键值对，也可以是文件参数。

多文件上传封装


public static void ExecuteMultipartRequest(HttpWebRequest request, List<KeyValue> nvc)
{
  Console.WriteLine(request.Headers);
  //  log.Debug(string.Format("Uploading {0} to {1}", file, url));
  string boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x");
  byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "\r\n");

  HttpWebRequest wr = request;
  wr.ContentType = "multipart/form-data; boundary=" + boundary;
  wr.Method = "POST";
  wr.KeepAlive = true;
  wr.Credentials = System.Net.CredentialCache.DefaultCredentials;



  using (var rs = wr.GetRequestStream())
  {
    // 普通参数模板
    string formdataTemplate = "Content-Disposition: form-data; name=\"{0}\"\r\n\r\n{1}";
    //带文件的参数模板
    string headerTemplate = "Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"\r\nContent-Type: {2}\r\n\r\n";
    foreach (KeyValue keyValue in nvc)
    {
      //如果是普通参数
      if (keyValue.FilePath == null)
      {
        rs.Write(boundarybytes, 0, boundarybytes.Length);
        string formitem = string.Format(formdataTemplate, keyValue.Key, keyValue.Value);
        byte[] formitembytes = System.Text.Encoding.UTF8.GetBytes(formitem);
        rs.Write(formitembytes, 0, formitembytes.Length);
      }
      //如果是文件参数,则上传文件
      else
      {
        rs.Write(boundarybytes, 0, boundarybytes.Length);

        string header = string.Format(headerTemplate, keyValue.Key, keyValue.FilePath, keyValue.ContentType);
        byte[] headerbytes = System.Text.Encoding.UTF8.GetBytes(header);
        rs.Write(headerbytes, 0, headerbytes.Length);

        using (var fileStream = new FileStream(keyValue.FilePath, FileMode.Open, FileAccess.Read))
        {
          byte[] buffer = new byte[4096];
          int bytesRead = 0;
          long total = 0;
          while ((bytesRead = fileStream.Read(buffer, 0, buffer.Length)) != 0)
          {

            rs.Write(buffer, 0, bytesRead);
            total += bytesRead;
          }
        }
      }
      
    }

    byte[] trailer = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "--\r\n");
    rs.Write(trailer, 0, trailer.Length);

  }

}

使用


static void Main(string[] args)
    {
	var request = WebRequest.Create("http://localhost:8080/test/upload") as HttpWebRequest;
      List<KeyValue> keyValues = new List<KeyValue>();
      keyValues.Add(new KeyValue("key1","param1"));
      keyValues.Add(new KeyValue("key2", "param2"));
      keyValues.Add(new KeyValue("file","test1.png","image/png"));
      keyValues.Add(new KeyValue("file", "test2.png", "image/png"));

      EasyHttp.ExecuteMultipartRequest(request,keyValues);
    }

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