这篇文章主要为大家详细介绍了SpringSecurity如何实现用户名密码登录功能,文中的示例代码讲解详细,感兴趣的小伙伴可以跟随小编一起了解一下
环境
JDK 1.8
Spring Boot 2.3.0.RELEASE
Maven 3.6.1
H2 数据库
用户名密码登录
首先,我们用 Spring Security 实现用户输入用户名密码登录验证并获取相应权限。
E-R图
完整建表语句
因为是测试程序,所以用H2数据库来测试。SQL脚本在resouces/db目录下,项目启动后会自动初始化脚本,无需手动执行。
schema.sql
DROP TABLE IF EXISTS `SYS_ROLE`;
DROP TABLE IF EXISTS `SYS_USER_ROLE`;
DROP TABLE IF EXISTS `SYS_USER`;
create table SYS_ROLE
(
ID INT not null primary key,
NAME VARCHAR(255) not null
);
create table SYS_USER
(
ID INT not null primary key,
NAME VARCHAR not null,
PASSWORD VARCHAR(255) not null
);
create table SYS_USER_ROLE
(
USER_ID INT not null,
ROLE_ID INT not null,
constraint pk_1 primary key (ROLE_ID, USER_ID),
constraint fk_1 foreign key (ROLE_ID) references SYS_ROLE (ID) on update cascade on delete cascade,
constraint fk_2 foreign key (USER_ID) references SYS_USER (ID) on update cascade on delete cascade
);
data.sql
INSERT INTO `SYS_ROLE` (`ID`, `NAME`) VALUES (1, 'ADMIN'),(2, 'USER');
INSERT INTO `SYS_USER` (`ID`, `NAME`, `PASSWORD`) VALUES (1, 'super', '888888'), (2, 'jack', '666666'), (3, 'lucy', '999999');
INSERT INTO `SYS_USER_ROLE` (`USER_ID`, `ROLE_ID`) VALUES (1, 1),(2, 2),(3, 2);
准备好建表语句后,完成实体类的编写
SysRole.java
package org.hui.login.model;
/**
* 用户角色
* @author zenghui
* @date 2020-05-20
*/
public class SysRole {
private Integer id;
private String name;
public Integer getId() {return id;}
public void setId(Integer id) {this.id = id;}
public String getName() {return name;}
public void setName(String name) {this.name = name;}
}
SysUser.java
package org.hui.login.model;
/**
* 用户基本信息
* @author zenghui
* @date 2020-05-20
*/
public class SysUser {
private Integer id;
private String name;
private String password;
public Integer getId() {return id;}
public void setId(Integer id) {this.id = id;}
public String getName() {return name;}
public void setName(String name) {this.name = name;}
public String getPassword() {return password;}
public void setPassword(String password) {this.password = password;}
}
SysUserRole.java
package org.hui.login.model;
/**
* 角色和用户对应关系
* @author zenghui
* @date 2020-05-20
*/
public class SysUserRole {
private Integer userId;
private Integer roleId;
public Integer getUserId() {return userId;}
public void setUserId(Integer userId) {this.userId = userId;}
public Integer getRoleId() {return roleId;}
public void setRoleId(Integer roleId) {this.roleId = roleId;}
}
以上,完成了数据层的设计。
POM依赖
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 https://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>2.3.0.RELEASE</version>
<relativePath/> <!-- lookup parent from repository -->
</parent>
<groupId>example</groupId>
<artifactId>spring-login</artifactId>
<version>0.0.1-SNAPSHOT</version>
<name>spring-login</name>
<description>Spring Security to implements Login</description>
<properties>
<java.version>1.8</java.version>
</properties>
<dependencies>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-security</artifactId>
</dependency>
<dependency>
<groupId>org.mybatis.spring.boot</groupId>
<artifactId>mybatis-spring-boot-starter</artifactId>
<version>2.1.2</version>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<dependency>
<groupId>com.h2database</groupId>
<artifactId>h2</artifactId>
<scope>runtime</scope>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
</plugin>
</plugins>
</build>
</project>
配置文件
application.properties
spring.datasource.url=jdbc:h2:mem:userdb
spring.datasource.driverClassName=org.h2.Driver
spring.datasource.username=sa
spring.datasource.password=123
#设置SQL脚本的位置,resources/db目录下,如果不设置的话,默认就在resources目录下
spring.datasource.schema=classpath:db/schema.sql
spring.datasource.data=classpath:db/data.sql
#H2控制台启用
spring.h2.console.enabled=true
#访问H2的URL
spring.h2.console.path=/h2
# 下划线转化为驼峰命名
mybatis.configuration.map-underscore-to-camel-case=true
Mapper
采用了Mybatis来操作数据库。
准备好需要的几个Mapper,如下
SysRoleMapper.java
package org.hui.login.mapper;
import org.apache.ibatis.annotations.Mapper;
import org.apache.ibatis.annotations.Select;
import org.hui.login.model.SysRole;
/**
* @author zenghui
* @date 2020-05-20
*/
@Mapper
public interface SysRoleMapper {
@Select("SELECT * FROM sys_role WHERE id = #{id}")
SysRole selectById(Integer id);
}
SysUserMapper.java
package org.hui.login.mapper;
import org.apache.ibatis.annotations.Mapper;
import org.apache.ibatis.annotations.Select;
import org.hui.login.model.SysUser;
/**
* @author zenghui
* @date 2020-05-20
*/
@Mapper
public interface SysUserMapper {
@Select("SELECT * FROM sys_user WHERE name = #{name}")
SysUser selectByName(String name);
}
SysUserRoleMapper.java
package org.hui.login.mapper;
import org.apache.ibatis.annotations.Mapper;
import org.apache.ibatis.annotations.Select;
import org.hui.login.model.SysUserRole;
import java.util.List;
/**
* @author zenghui
* @date 2020-05-20
*/
@Mapper
public interface SysUserRoleMapper {
@Select("SELECT * FROM sys_user_role WHERE user_id = #{userId}")
List<SysUserRole> listByUserId(Integer userId);
}
Service设计
Spring Security提供了一个UserDetailsService接口,我们需要实现这个接口的loadUserByUsername方法,用于用户信息的获取,如果存在用户,则把用户的密码获取出来,如果不存在这个用户,直接抛异常。
我们新建一个SysUserDetailService.java
package org.hui.login.service;
import org.hui.login.mapper.SysRoleMapper;
import org.hui.login.mapper.SysUserMapper;
import org.hui.login.mapper.SysUserRoleMapper;
import org.hui.login.model.SysRole;
import org.hui.login.model.SysUser;
import org.hui.login.model.SysUserRole;
import org.springframework.security.core.GrantedAuthority;
import org.springframework.security.core.authority.SimpleGrantedAuthority;
import org.springframework.security.core.userdetails.User;
import org.springframework.security.core.userdetails.UserDetails;
import org.springframework.security.core.userdetails.UserDetailsService;
import org.springframework.security.core.userdetails.UsernameNotFoundException;
import org.springframework.stereotype.Service;
import java.util.ArrayList;
import java.util.Collection;
import java.util.List;
/**
* @author zenghui
* @date 2020-05-20
*/
@Service
public class SysUserDetailService implements UserDetailsService {
private final SysUserMapper sysUserMapper;
private final SysRoleMapper sysRoleMapper;
private final SysUserRoleMapper sysUserRoleMapper;
public SysUserDetailService(SysUserMapper sysUserMapper, SysRoleMapper sysRoleMapper, SysUserRoleMapper sysUserRoleMapper) {
this.sysUserMapper = sysUserMapper;
this.sysRoleMapper = sysRoleMapper;
this.sysUserRoleMapper = sysUserRoleMapper;
}
@Override
public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
Collection<GrantedAuthority> authorities = new ArrayList<>();
// 从数据库中取出用户信息
SysUser user = sysUserMapper.selectByName(username);
// 判断用户是否存在
if(user == null) {
throw new UsernameNotFoundException("用户名不存在");
}
// 添加权限
List<SysUserRole> userRoles = sysUserRoleMapper.listByUserId(user.getId());
for (SysUserRole userRole : userRoles) {
SysRole role = sysRoleMapper.selectById(userRole.getRoleId());
authorities.add(new SimpleGrantedAuthority(role.getName()));
}
// 返回UserDetails实现类
return new User(user.getName(), user.getPassword(), authorities);
}
}
如果用户存在,则会进行密码的校验,方便起见,密码我们假设储存为明文,实际上密码有很多加密的策略,这个后序可以自己配置,密码校验在SecurityConfig这个类中,代码如下:
package org.hui.login.config;
import org.hui.login.service.SysUserDetailService;
import org.springframework.context.annotation.Configuration;
import org.springframework.security.config.annotation.authentication.builders.AuthenticationManagerBuilder;
import org.springframework.security.config.annotation.method.configuration.EnableGlobalMethodSecurity;
import org.springframework.security.config.annotation.web.builders.HttpSecurity;
import org.springframework.security.config.annotation.web.builders.WebSecurity;
import org.springframework.security.config.annotation.web.configuration.EnableWebSecurity;
import org.springframework.security.config.annotation.web.configuration.WebSecurityConfigurerAdapter;
import org.springframework.security.crypto.password.PasswordEncoder;
/**
* @author zenghui
* @date 2020-05-20
*/
@Configuration
@EnableWebSecurity
@EnableGlobalMethodSecurity(prePostEnabled = true)
public class SecurityConfig extends WebSecurityConfigurerAdapter {
private final SysUserDetailService sysUserDetailService;
public SecurityConfig(SysUserDetailService sysUserDetailService) {
this.sysUserDetailService = sysUserDetailService;
}
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.userDetailsService(sysUserDetailService).passwordEncoder(new PasswordEncoder() {
@Override
public String encode(CharSequence charSequence) {
return charSequence.toString();
}
@Override
public boolean matches(CharSequence charSequence, String s) {
return s.equals(charSequence.toString());
}
});
}
@Override
protected void configure(HttpSecurity http) throws Exception {
http.authorizeRequests().anyRequest().authenticated()
.and().formLogin().loginPage("/login").defaultSuccessUrl("/").permitAll()
.and().logout().permitAll();
// 关闭CSRF跨域
http.csrf().disable();
}
@Override
public void configure(WebSecurity web) {
web.ignoring().antMatchers("/css/**", "/js/**");
}
}
以上便完成了所有后端代码的编写,接下来,完成controller和前端页面的编写。
HTML
在resources的static目录下,新建两个html文件
login.html
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>登录页</title>
</head>
<body>
<form action="/login" method="post">
用户名:<input type="text" name="username">
密码:<input type="password" name="password">
<button type="submit">登录</button>
</form>
</body>
</html>
home.html
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>主页</title>
</head>
<body>
登录成功
</body>
</html>
Controller
新建一个LoginController,用于接收前端请求
package org.hui.login.controller;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
/**
* @author zenghui
* @date 2020-05-20
*/
@Controller
public class LoginController {
@RequestMapping("/")
public String home() {
return "home.html";
}
@RequestMapping("/login")
public String login() {
return "login.html";
}
}
启动
运行以下主程序
package org.hui.login;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
/**
* @author zenghui
* @date 2020-05-20
*/
@SpringBootApplication
public class LoginApplication {
public static void main(String[] args) {
SpringApplication.run(LoginApplication.class, args);
}
}
访问 http://localhost:8080/login
显示登录页面,输入用户名密码,点击登录,即可看到效果。
完整代码
Github
Gitee
以上就是Spring Security实现用户名密码登录详解的详细内容,更多关于Spring Security用户名密码登录的资料请关注编程学习网其它相关文章!
本文标题为:Spring Security实现用户名密码登录详解
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