避免在标准容器中默认构建元素

I'm interested in building an uninitialized_vector container, which will be semantically identical to std::vector with the caveat that new elements which otherwise would be created with a no-argument constructor will instead be created without initialization. I'm primarily interested in avoiding initializing POD to 0. As far as I can tell, there's no way to accomplish this by combining std::vector with a special kind of allocator.

我想以与 std::stack 相同的方式构建我的容器，它适应用户提供的容器(在我的例子中，std::vector).换句话说，我想避免重新实现整个 std::vector 而是在它周围提供一个外观".

I'd like to build my container in the same vein as std::stack, which adapts a user-provided container (in my case, std::vector). In other words, I'd like to avoid reimplementing the entirety of std::vector and instead provide a "facade" around it.

有没有一种简单的方法可以从 std::vector 的外部"控制默认构造?

Is there a simple way to control default construction from the "outside" of std::vector?

这是我得到的解决方案，这启发了 Kerrek 的回答:

Here's the solution I arrived at, which was inspired Kerrek's answer:

#include <iostream>
#include <vector>
#include <memory>
#include <algorithm>
#include <cassert>

// uninitialized_allocator adapts a given base allocator
// uninitialized_allocator's behavior is equivalent to the base
// except for its no-argument construct function, which is a no-op
template<typename T, typename BaseAllocator = std::allocator<T>>
  struct uninitialized_allocator
    : BaseAllocator::template rebind<T>::other
{
  typedef typename BaseAllocator::template rebind<T>::other super_t;

  template<typename U>
    struct rebind
  {
    typedef uninitialized_allocator<U, BaseAllocator> other;
  };

  // XXX for testing purposes
  typename super_t::pointer allocate(typename super_t::size_type n)
  {
    auto result = super_t::allocate(n);

    // fill result with 13 so we can check afterwards that
    // the result was not default-constructed
    std::fill(result, result + n, 13);
    return result;
  }

  // catch default-construction
  void construct(T *p)
  {
    // no-op
  }

  // forward everything else with at least one argument to the base
  template<typename Arg1, typename... Args>
    void construct(T* p, Arg1 &&arg1, Args&&... args)
  {
    super_t::construct(p, std::forward<Arg1>(arg1), std::forward<Args>(args)...);
  }
};

namespace std
{

// XXX specialize allocator_traits
//     this shouldn't be necessary, but clang++ 2.7 + libc++ has trouble
//     recognizing that uninitialized_allocator<T> has a well-formed
//     construct function
template<typename T>
  struct allocator_traits<uninitialized_allocator<T> >
    : std::allocator_traits<std::allocator<T>>
{
  typedef uninitialized_allocator<T> allocator_type;

  // for testing purposes, forward allocate through
  static typename allocator_type::pointer allocate(allocator_type &a, typename allocator_type::size_type n)
  {
    return a.allocate(n);
  }

  template<typename... Args>
    static void construct(allocator_type &a, T* ptr, Args&&... args)
  {
    a.construct(ptr, std::forward<Args>(args)...);
  };
};

}

// uninitialized_vector is implemented by adapting an allocator and
// inheriting from std::vector
// a template alias would be another possiblity

// XXX does not compile with clang++ 2.9
//template<typename T, typename BaseAllocator>
//using uninitialized_vector = std::vector<T, uninitialized_allocator<T,BaseAllocator>>;

template<typename T, typename BaseAllocator = std::allocator<T>>
  struct uninitialized_vector
    : std::vector<T, uninitialized_allocator<T,BaseAllocator>>
{};

int main()
{
  uninitialized_vector<int> vec;
  vec.resize(10);

  // everything should be 13
  assert(std::count(vec.begin(), vec.end(), 13) == vec.size());

  // copy construction should be preserved
  vec.push_back(7);
  assert(7 == vec.back());

  return 0;
}

此解决方案的工作方式取决于特定供应商的编译器和STL 的 std::vector 实现符合 c++11.

This solution will work depending on how closely a particular vendor's compiler & STL's std::vector implementation conforms to c++11.

推荐答案

我认为问题归结为容器对元素执行的初始化类型.比较:

I think the problem boils down to the type of initialization that the container performs on elements. Compare:

T * p1 = new T;   // default-initalization
T * p2 = new T(); // value-initialization

标准容器的问题在于它们采用默认参数进行值初始化，如 resize(size_t, T = T()).这意味着没有优雅的方法可以避免值初始化或复制.(对于构造函数也是如此.)

The problem with the standard containers is that they take the default argument to be value initialized, as in resize(size_t, T = T()). This means that there's no elegant way to avoid value-initialization or copying. (Similarly for the constructor.)

即使使用标准分配器也不起作用，因为它们的中心 construct() 函数接受了一个值初始化的参数.您宁愿需要的是一个使用默认初始化的 construct():

Even using the standard allocators doesn't work, because their central construct() function takes an argument that becomes value-initialized. What you would rather need is a construct() that uses default-initialization:

template <typename T>
void definit_construct(void * addr)
{
  new (addr) T;  // default-initialization
}

这样的东西将不再是符合标准的分配器，但您可以围绕这个想法构建自己的容器.

Such a thing wouldn't be a conforming standard allocator any more, but you could build your own container around that idea.

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