Derived class not inheriting overloaded method from base class(派生类不从基类继承重载方法)
问题描述
I would like to have a method in a base class call a pure virtual method that will be implemented in a derived class. However, the base class parameterless method doesn't seem to be inherited by the derived class. What am I doing wrong? Compiler is MSVC12.
error C2660: 'Derived::load' : function does not take 0 arguments
Here is a complete example (that doesn't compile due to the error):
struct Base
{
void load() { load(42); }; // Making this virtual doesn't matter.
virtual void load(int i) = 0;
};
struct Derived : Base
{
virtual void load(int i) {};
};
int main()
{
Derived d;
d.load(); // error C2660: 'Derived::load' : function does not take 0 arguments
}
Oh, the derived class does inherit void load()
.
But you are declaring void load(int i)
in the derived class, which means it is shadowed.
Add using Base::load;
to Derived
to add all non-overridden definitions of load
from Base
to the overload-set in Derived
.
Alternatively, call the Base
-class-version explicitly with the scope-resolution-operator d.Base::load();
.
这篇关于派生类不从基类继承重载方法的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:派生类不从基类继承重载方法
基础教程推荐
- 设计字符串本地化的最佳方法 2022-01-01
- C++ 程序在执行 std::string 分配时总是崩溃 2022-01-01
- 什么是T&&(双与号)在 C++11 中是什么意思? 2022-11-04
- 您如何将 CreateThread 用于属于类成员的函数? 2021-01-01
- C++,'if' 表达式中的变量声明 2021-01-01
- C++ 标准:取消引用 NULL 指针以获取引用? 2021-01-01
- 如何定义双括号/双迭代器运算符,类似于向量的向量? 2022-01-01
- 调用std::Package_TASK::Get_Future()时可能出现争用情况 2022-12-17
- 如何在 C++ 中处理或避免堆栈溢出 2022-01-01
- 运算符重载的基本规则和习语是什么? 2022-10-31