c# Alpha 电话号码翻译器

c# Alpha Telephone Number Translator(c# Alpha 电话号码翻译器)

问题描述

我有一个家庭作业，程序将接受格式类似于 555-GET-FOOD 的任何电话号码.任务是将字母映射到数字，并将数字转换为等效的数字.
例如:A、B、C = 2；D、E、F = 3；等等……

I have a homework assignment where the program will accept any phone number in the format similar to 555-GET-FOOD. The task is to map the alphabetic letters to numbers and translate the number to its numeric equivalent.
For example: A, B, C = 2; D, E, F = 3; etc...

此时我们还没有介绍类或创建地图，因此这些不是可行的解决方案.本章确实涵盖了枚举，所以我正在努力使用枚举类型来解决.我设置了一种方法来验证数据(确保正确的字符数和连字符在正确的位置)，并且确实可以正常工作.我设置了另一种方法来删除连字符，并且还使用了 ToUpper() 方法，这也可以正常工作，因此在这两种方法已经完成后，我使用数字设置了 foreach 循环.

We have not covered Classes or creating maps at this point so these would not be viable solutions. This chapter does cover the enum so I am working to solve using an Enumerated type. I have a method set up to validate the data (ensure the correct # of characters and the hyphens are in the correct place) and this does work correctly. I have another method set up to remove the hyphens and also uses the ToUpper() method and this also works correctly, so the foreach loop I have set up us using the number after these two methods have already finished.

我还设置了一种在转换发生后运行以重新添加连字符的方法，这也有效.

I have also set up a method to run after the conversion takes place to add the hyphens back in and this also works.

我已经尝试了几种方法来获得工作，并将它们留在注释掉它们可能是我需要使用的机会，因为我尝试使用 switch 语句，我现在只使用字母 A 设置，并计划完成剩余的信件，如果我能够让它工作的话.我认为我的问题是 foreach 循环使用的是 char 类型，而开关使用的是 int.在 foreach 循环中尝试代码时似乎是同样的问题，但我不知道如何解决，所以任何建议都值得赞赏.

I have tried several ways to get is to work and have left them in commented out on the chance they might be what I need to use, for my attempt with the switch statement I only set up with the letter A for now, and plan to finish the remaining letters if I am able to get this to work. I think the one my issues is the foreach loop is using a char type and the switch is using an int. Seems to be the same issue when trying the code inside the foreach loop but I am not sure how to fix so any suggestions are appreciated.

public enum AlphaNumber
{ 
    A=2, B=2, C=2, D=3, E=3, F=3, G=4, H=4, I=4, J=5, K=5, L=5, 
    M=6, N=6, O=6, P=7, Q=7, R=7, S=8, T=8, U=8, V=9, W=9, X=9, Y=9, Z=9
}
 private void UpdatePhone(AlphaNumber phone)
    {
        switch (phone)
        {
            case AlphaNumber.A:
           //return AlphaNumber.(int[])Enum.GetValues(typeof(AlphaNumber));
           //return (Enum.GetValues(typeof(AlphaNumber)));
           //   (int)ValueType;
                Enum.GetValues(typeof(AlphaNumber));
                break;                   
        }
private void translateButton_Click(object sender, EventArgs e)
    {
        numberLabel.Text = "";//Clear the numberLabel
        //Get a trimmed copy of the user's input.  
        string input = numberTextBox.Text.Trim();

        if (IsValidFormat(input))
        {
            Unformat(ref input);

            foreach (char ch in input)
            {
                if (char.IsLetter(ch))//                    {
                    ch = (char)Enums.AlphaNumber.Active;
                    //ch = (char)Enum.GetValues(typeof(AlphaNumber));
                    //ch = Enum.TryParse(AlphaNumber);
                   // ch = AlphaNumber.(int[])Enum.GetValues(typeof(AlphaNumber));
                    //UpdatePhone(ch);
                   MessageBox.Show("Character is char");                    }
            }

            TelephoneFormat(ref input);    
            numberLabel.Text = input;

我愿意接受任何建议并感谢提供的任何帮助.我需要帮助的地方是在 foreach 循环中，我正在查看每个值，如果它是一个字母，我想从枚举值中获取值并将 char 替换为数字值.

I am open to any suggestions and appreciate any help provided. Where I need help is inside the foreach loop, I am looking at each value and if it is a letter I want to get the value from the enum values and replace the char with the number value.

推荐答案

删除 enum 和 switch，改为查找地图.我创建了一个 .NET Fiddle 来演示此操作是否按要求进行here.

Drop the enum and the switch, and instead do a lookup against a map. I have created a .NET Fiddle that demonstrates this working as desired here.

但如果使用 Dictionary<char, char> 出于某种奇怪的原因是不可能的，那么我想你可以使用 这个版本——我在其中使用了enum.只是需要做更多的工作，而且活动部件越多，维护起来就越困难.

But if using a Dictionary<char, char> is for some odd reason out of question, then I suppose you could use this version -- in which I use the enum. It is just a lot more work and the more moving parts you have the harder it is to maintain.

在 C# 中，类型 enum 默认继承自 int，但您可以指定各种其他数字类型——例如 byte 或 long 等...其中一个关键要点是装箱/拆箱和从一种类型转换/转换为另一种类型的概念.如果您有一个 enum 定义为 enum Foo { Bar = 63 } 和 您尝试将其cast转换为char您希望得到什么?

In C# the type enum inherits from int by default, but you can specify various other numeric types -- like byte or long, etc... One of the key takeaways is the concept of boxing/unboxing and casting/converting from one type to another. If you have an enum defined as enum Foo { Bar = 63 } and you try to cast it to a char what would you expect to get?

这实际上会产生字符 ? -- 看看 ASCII 表 并找到 63 的 DEC 并查看它映射到 Char 列的内容.

This actually would result in the char ? -- take a look at the ASCII table and the find the DEC for 63 and look at what it maps to for the Char column.

这个疯狂的复杂混乱解决了这个问题:

The issue is fixed with this crazy complicated mess:

    public enum AlphaNumber
    { 
        A=2, B=2, C=2, D=3, E=3, F=3, G=4, H=4, I=4, J=5, K=5, L=5, 
        M=6, N=6, O=6, P=7, Q=7, R=7, S=8, T=8, U=8, V=9, W=9, X=9, Y=9, Z=9
    }

    public static class PhoneNumber
    {
        public static char ParseInput(char input)
        {
            if (input == '-' || char.IsDigit(input))
            {
                return input;
            }

            if (char.IsLetter(input))
            {
                var num = (AlphaNumber)(Enum.Parse(typeof(AlphaNumber), (char.IsLower(input) ? char.ToUpperInvariant(input) : input).ToString()));
                return ((int)num).ToString()[0];
            }

            return '';
        }
    }

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