将一个类的对象转换为另一个类的对象

Converting object of a class to of another one(将一个类的对象转换为另一个类的对象)

问题描述

除了存储在其中的数据类型外，我有两个几乎相等的类.一个类包含所有双精度值，而另一个包含所有浮点值.

I have two classes which have are nearly equal except the data types stored in them. One class contains all double values while other contains all float values.

class DoubleClass
{
    double X;
    double Y;
    double Z;
}

class FloatClass
{
    float X;
    float Y;
    float Z;
}

现在我有一个 DoubleClass 点，我想将其转换为 FloatClass.

Now I have a point of DoubleClass which I want to convert to FloatClass.

var doubleObject = new DoubleClass();

var convertedObject = (FloatClass)doubleObject; // TODO: This

一种简单的方法是创建一个方法来创建一个新的 FloatClass 对象，填充所有值并返回它.有没有其他有效的方法来做到这一点.

One simple way is to make a method which creates a new FloatClass object, fills all values and return it. Is there any other efficient way to do this.

推荐答案

使用转换运算符:

public static explicit operator FloatClass (DoubleClass c) {
   FloatCass fc = new FloatClass();
   fc.X = (float) c.X;
   fc.Y = (float) c.Y;
   fc.Z = (float) c.Z;
   return fc;
}

然后就用它吧:

var convertedObject = (FloatClass) doubleObject;

编辑

我将运算符更改为 explicit 而不是 implicit 因为我在示例中使用了 FloatClass 强制转换.我更喜欢使用 explicit 而不是 implicit 所以它迫使我确认对象将被转换为 的类型(对我来说这意味着更少的干扰错误 + 可读性).

I changed the operator to explicit instead of implicit since I was using a FloatClass cast in the example. I prefer to use explicit over implicit so it forces me to confirm what type the object will be converted to (to me it means less distraction errors + readability).

但是，您可以使用 implicit 转换，然后您只需要这样做:

However, you can use implicit conversion and then you would just need to do:

var convertedObject = doubleObject;

参考

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