MYSQL: Sequential Number Table(MYSQL:序号表)
问题描述
我正在尝试获取从 1 到 2000 万的序列号表.(或 0 到 2000 万)
I am trying to get a sequential number table from 1 to 20 million. (or 0 to 20 million)
对于这个常见问题获得与 MySQL 兼容的解决方案是多么困难,我感到非常震惊.
I am rather awestruck at how difficult it's been to get a MySQL-compatible solution to this common problem.
与此类似:创建一个数字表"在 MySQL 中
但答案只有 100 万.我不太了解位移计算.
But the answer only goes to 1 million. I am not really understanding the bit shift calculations.
我看过很多 SQL 答案,但大多数都是针对非 MySQL 的数据库,所以由于缺乏对 MySQL 和其他方面的了解,我无法采用这些代码.
I've seen many SQL answers but most are for databases that aren't MySQL, so I can't adopt the code due to lack of knowledge of both MySQL and the other.
一些参考资料:
SQL,数字辅助表
什么是最好的方法创建和填充数字表?
请确保您发布的代码在 MySQL 中兼容并且以分号分隔,以便我可以在 PhpMyAdmin 中运行它.我希望将表命名为 numbers
并带有名为 i
Please make sure the code you post is compatible in MySQL and is semicolon delimited so I can run it in PhpMyAdmin. I'd appreciate the table to be named numbers
with the column called i
我将对每个解决方案进行基准测试,以便将其存档,并希望在下次有人尝试搜索此问题时显示出来.
I will benchmark each solution, so the it's archived and hopefully will show up for the next time someone tries to search for this problem.
到目前为止的基准:
时间以秒为单位.
+---------------+------------------+---------+-----------+------------+
| Author | Method | 10,000 | 1,000,000 | 20,000,000 |
+---------------+------------------+---------+-----------+------------+
| Devon Bernard | PHP Many Queries | 0.38847 | 39.32716 | ~ 786.54 |
| Bhare | PHP Few Queries | 0.00831 | 0.94738 | 19.58823 |
| psadac,Bhare | LOAD DATA | 0.00549 | 0.43855 | 10.55236 |
| kjtl | Bitwise | 1.36076 | 1.48300 | 4.79226 |
+---------------+------------------+---------+-----------+------------+
推荐答案
-- To use the bitwise solution you need a view of 2 to the power 25.
-- the following solution is derived from http://stackoverflow.com/questions/9751318/creating-a-numbers-table-in-mysql
-- the following solution ran in 43.8 seconds with the primary key, without it 4.56 seconds.
-- create a view that has 2 to the power 25 minus 1
-- 2 ^ 1
CREATE or replace VIEW `two_to_the_power_01_minus_1` AS select 0 AS `n` union all select 1 AS `1`;
-- 2 ^ 2
CREATE or replace VIEW `two_to_the_power_02_minus_1`
AS select
((`hi`.`n` << 1) | `lo`.`n`) AS `n`
from (`two_to_the_power_01_minus_1` `lo` join `two_to_the_power_01_minus_1` `hi`) ;
-- 2 ^ 4
CREATE or replace VIEW `two_to_the_power_04_minus_1`
AS select
((`hi`.`n` << 2 ) | `lo`.`n`) AS `n`
from (`two_to_the_power_02_minus_1` `lo` join `two_to_the_power_02_minus_1` `hi`) ;
-- 2 ^ 8
CREATE or replace VIEW `two_to_the_power_08_minus_1`
AS select
((`hi`.`n` << 4 ) | `lo`.`n`) AS `n`
from (`two_to_the_power_04_minus_1` `lo` join `two_to_the_power_04_minus_1` `hi`) ;
-- 2 ^ 12
CREATE or replace VIEW `two_to_the_power_12_minus_1`
AS select
((`hi`.`n` << 8 ) | `lo`.`n`) AS `n`
from (`two_to_the_power_08_minus_1` `lo` join `two_to_the_power_04_minus_1` `hi`) ;
-- 2 ^ 13
CREATE or replace VIEW `two_to_the_power_13_minus_1`
AS select
((`hi`.`n` << 1) | `lo`.`n`) AS `n`
from (`two_to_the_power_01_minus_1` `lo` join `two_to_the_power_12_minus_1` `hi`);
-- create a table to store the interim results for speed of retrieval
drop table if exists numbers_2_to_the_power_13_minus_1;
create table `numbers_2_to_the_power_13_minus_1` (
`i` int(11) unsigned
) ENGINE=myisam DEFAULT CHARSET=latin1 ;
-- faster 2 ^ 13
insert into numbers_2_to_the_power_13_minus_1( i )
select n from `two_to_the_power_13_minus_1` ;
-- faster 2 ^ 12
CREATE or replace view `numbers_2_to_the_power_12_minus_1`
AS select
`numbers_2_to_the_power_13_minus_1`.`i` AS `i`
from `numbers_2_to_the_power_13_minus_1`
where (`numbers_2_to_the_power_13_minus_1`.`i` < (1 << 12));
-- faster 2 ^ 25
CREATE or replace VIEW `numbers_2_to_the_power_25_minus_1`
AS select
((`hi`.`i` << 12) | `lo`.`i`) AS `i`
from (`numbers_2_to_the_power_12_minus_1` `lo` join `numbers_2_to_the_power_13_minus_1` `hi`);
-- create table for results
drop table if exists numbers ;
create table `numbers` (
`i` int(11) signed
, primary key(`i`)
) ENGINE=myisam DEFAULT CHARSET=latin1;
-- insert the numbers
insert into numbers(i)
select i from numbers_2_to_the_power_25_minus_1
where i <= 20000000 ;
drop view if exists numbers_2_to_the_power_25_minus_1 ;
drop view if exists numbers_2_to_the_power_12_minus_1 ;
drop table if exists numbers_2_to_the_power_13_minus_1 ;
drop view if exists two_to_the_power_13_minus_1 ;
drop view if exists two_to_the_power_12_minus_1 ;
drop view if exists two_to_the_power_08_minus_1 ;
drop view if exists two_to_the_power_04_minus_1 ;
drop view if exists two_to_the_power_02_minus_1 ;
drop view if exists two_to_the_power_01_minus_1 ;
这篇关于MYSQL:序号表的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:MYSQL:序号表
基础教程推荐
- 使用pyodbc“不安全"的Python多处理和数据库访问? 2022-01-01
- ERROR 2006 (HY000): MySQL 服务器已经消失 2021-01-01
- 在 VB.NET 中更新 SQL Server DateTime 列 2021-01-01
- Sql Server 字符串到日期的转换 2021-01-01
- 如何在 SQL Server 的嵌套过程中处理事务? 2021-01-01
- SQL Server 中单行 MERGE/upsert 的语法 2021-01-01
- 将数据从 MS SQL 迁移到 PostgreSQL? 2022-01-01
- SQL Server:只有 GROUP BY 中的最后一个条目 2021-01-01
- SQL Server 2016更改对象所有者 2022-01-01
- 无法在 ubuntu 中启动 mysql 服务器 2021-01-01