Efficient way to find if map contains any of the keys from a list/iterable(查找映射是否包含列表/可迭代项中的任何键的有效方法)
问题描述
I need to check if a map contains any of the keys from a list, and if it does then return the first matching value. The naive approach that comes to mind is to do it in two nested loops:
Map<String, String> fields = new HashMap<String, String>();
fields.put("a", "value a");
fields.put("z", "value z");
String[] candidates = "a|b|c|d".split("|");
for (String key : fields.keySet()){
for (String candidate : candidates) {
if (key.equals(candidate)){
return fields.get(key);
}
}
}
Is there a nicer and more efficient way, possibly one relying on the Java standard library?
Surely something like:
for (String candidate : candidates) {
String result = fields.get(key);
if (result != null) {
return result;
}
}
The above only performs one map lookup per candidate key. It avoids the separate test for presence plus extraction, since extracting a non-existant key will simply give you a null. Note (thanks Slanec) that a null value for a valid key is indistinguishable from a non-existant key for this solution.
I don't quite understand why you're performing the case conversion, btw.
这篇关于查找映射是否包含列表/可迭代项中的任何键的有效方法的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:查找映射是否包含列表/可迭代项中的任何键的有效方法
基础教程推荐
- Spring Boot Freemarker从2.2.0升级失败 2022-01-01
- Java 中保存最后 N 个元素的大小受限队列 2022-01-01
- 如何强制对超级方法进行多态调用? 2022-01-01
- 首次使用 Hadoop,MapReduce Job 不运行 Reduce Phase 2022-01-01
- 由于对所需库 rt.jar 的限制,对类的访问限制? 2022-01-01
- 如何对 HashSet 进行排序? 2022-01-01
- 如何在不安装整个 WTP 包的情况下将 Tomcat 8 添加到 Eclipse Kepler 2022-01-01
- 如何使用 Eclipse 检查调试符号状态? 2022-01-01
- 如何使用 Stream 在集合中拆分奇数和偶数以及两者的总和 2022-01-01
- 在螺旋中写一个字符串 2022-01-01