未找到接口 java.util.List Rest API Spring boot 的主构造函数或默认构造函数

No primary or default constructor found for interface java.util.List Rest API Spring boot(未找到接口 java.util.List Rest API Spring boot 的主构造函数或默认构造函数)

本文介绍了未找到接口 java.util.List Rest API Spring boot 的主构造函数或默认构造函数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在将请求正文传递给邮递员的 POST 请求,类似于:

I am passing a request body to a POST request on postman similar to this:

 "name":"Mars",
"artifacts":[
   {
      "elements":[
         {
            "name":"carbon",
            "amount":0.5,
            "measurement":"g"
         }
      ],
      "typeName":"typeA"
   },
   {
      "elements":[
         {
            "name":"hydrogen",
            "amount":0.2,
            "measurement":"g"
         }
      ],
      "typeName":"typeB"
   }
]

rest 控制器中的 create 方法如下所示.

The create method in the rest controller looks like this.

  @RequestMapping("/create")
  public Planet create(@RequestBody Planet data) {
      Planet mars = planetService.create(data.getName(),data.getArtifacts());
      return mars;

Planet 及其所有嵌套对象都有一个默认构造函数,例如:

Planet and all its nested objects have a default constructor such as:

public Planet() {}

但是,由于缺少默认构造函数,我无法创建新的行星对象.请帮忙!

However, I am not able to create a new planet object because of lack of a default constructor. Please help!

行星类

public class Planet {
@JsonProperty("name")
private String name;
@Field("artifacts")
private List<Artifact> artifacts;

public Planet() {}

public Planet(String name, List<Artifact> artifacts)
{
this.name = name;
this.artifacts = artifacts;
}
//setters and getters

}

工件类:

public class Artifact() {
@Field("elements")
private List<Element> elements;
@JsonProperty("typeName")
private String typeName;

public Artifact() {}

public Artifact(String typeName, List<Element> elements)
{
this.typeName = typeName;
this.elements = elements;
}
}

元素类:

public class Element() {
@JsonProperty("elementName")
private String name;
@JsonProperty("amount")
private double amount;
@JsonProperty("measurement")
private String measurement;

public Element() {}

public Element(String name, double amount, String measurement)
{
//assignments
}
}

推荐答案

我不明白你所面临的问题是什么,但我可以立即看到一个错误,所以猜测这就是你所面临的问题,我是会给你一个解决方案.

I don't understand what is the issue you are facing, but i can see an error straight away so guessing that is the issue you are facing, i am going to give you a solution.

创建一个与您的 json 数据结构匹配的类,如下所示:

Create a class which matches your json data structure like this :

Class PlanetData {
    private String name;
    private List<Planet> artifacts;

    public PlanetData(String name, List<Planet> artifacts){
        name = name;
        artifacts = artifacts;
    }

    // include rest of getters and setters here.
}

那么你的控制器应该是这样的.基本上,您需要将 @RequestBody 放入要从请求 JSON 接收的所有参数中.之前您只将 @RequestBody 放入名称参数而不是工件参数,并且由于请求正文只能使用一次,因此您需要一个包装类来使用单个 @RequestBody注释.

Then your controller should look like this. Basically you needed to put @RequestBody to all the parameters you want to recieve from request JSON. Earlier you only put @RequestBody to name parameter not artifact parameter and since Request Body can be consumed only once, so you need a wrapper class to recieve the complete request body using single @RequestBody annotation.

@RequestMapping("/create")
  public String create(@RequestBody PlanetData data) {
      Planet mars = planetService.create(data.getName(),data.getArtifacts());
      return mars.toString();
  }

查看 Planet 类,它还需要一些修改

Edit : Looking at the Planet class, it also needs some modification

public class Planet {
private String typeName; // key in json should match variable name for proper deserialization or you need to use some jackson annotation to map your json key to your variable name.
private List<Element> elements;

public Planet() {}

public Planet(String typeName, List<Element> elements)
{
this.typeName = typeName;
this.elements = elements;
}
//setters and getters. Remember to change your setters and getter from name to typeName.

}

希望这能解决您的问题.

Hope this solves your issue.

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