在 C++ 中初始化之前声明一个对象

Declaring an object before initializing it in c++(在 C++ 中初始化之前声明一个对象)

本文介绍了在 C++ 中初始化之前声明一个对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

是否可以在不实例化的情况下在 C++ 中声明变量?我想做这样的事情:

Is it possible to declare a variable in c++ without instantiating it? I want to do something like this:

Animal a;
if( happyDay() ) 
    a( "puppies" ); //constructor call
else
    a( "toads" );

基本上,我只想在条件之外声明一个,以便它获得正确的范围.

Basially, I just want to declare a outside of the conditional so it gets the right scope.

有没有办法在不使用指针和在堆上分配 a 的情况下做到这一点?也许有一些巧妙的参考资料?

Is there any way to do this without using pointers and allocating a on the heap? Maybe something clever with references?

推荐答案

您不能直接在 C++ 中执行此操作,因为对象是在使用默认构造函数定义时构造的.

You can't do this directly in C++ since the object is constructed when you define it with the default constructor.

但是,您可以首先运行参数化构造函数:

You could, however, run a parameterized constructor to begin with:

Animal a(getAppropriateString());

或者您实际上可以使用诸如 ?: 运算符 之类的东西来确定正确的字符串.(更新:@Greg 为此提供了语法.请参阅该答案)

Or you could actually use something like the ?: operator to determine the correct string. (Update: @Greg gave the syntax for this. See that answer)

这篇关于在 C++ 中初始化之前声明一个对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!

本文标题为:在 C++ 中初始化之前声明一个对象

基础教程推荐