如何一次将多个值分配给一个结构?

how to assign multiple values into a struct at once?(如何一次将多个值分配给一个结构?)

问题描述

我可以在 struct Foo 的初始化时执行此操作:

I can do this on initialization for a struct Foo:

Foo foo =  {bunch, of, things, initialized};

但是，我不能这样做:

Foo foo;
foo = {bunch, of, things, initialized};

那么，两个问题:

1. 为什么我不能做后者，前者是一个仅用于初始化的特殊构造函数吗?

2. 我该如何做类似于第二个例子的事情，即在一个结构体已经初始化之后，在一行代码中为它声明一堆变量?我试图避免对具有许多变量的大型结构执行此操作:

1. Why can't I do the latter, is the former a special constructor for initialization only?

2. How can I do something similar to the second example, i.e. declare a bunch of variables for a struct in a single line of code after it's already been initialized? I'm trying to avoid having to do this for large structs with many variables:

Foo foo;

foo.a = 1;
foo.b = 2;
foo.c = 3;
//... ad infinitum

推荐答案

第一个是聚合初始值设定项 - 您可以在此解决方案中阅读这些和标记初始值设定项:

The first is an aggregate initializer - you can read up on those and tagged initializers at this solution:

什么是标记结构初始化语法?

这是一种特殊的初始化语法，在你的结构初始化之后你不能做类似的事情.您可以做的是提供一个成员(或非成员)函数来将您的一系列值作为参数，然后您在成员函数中分配这些参数 - 这将允许您在结构以同样的方式初始化后完成此操作简洁(当然是在您第一次编写函数之后！)

It is a special initialization syntax, and you can't do something similar after initialization of your struct. What you can do is provide a member (or non-member) function to take your series of values as parameters which you then assign within the member function - that would allow you to accomplish this after the structure is initialized in a way that is equally concise (after you've written the function the first time of course!)

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