调整 C++ std::vector<char> 的大小无需初始化数据

Resizing a C++ std::vectorlt;chargt; without initializing data(调整 C++ std::vectorchar 的大小无需初始化数据)

问题描述

对于向量，可以假设元素连续存储在内存中，允许范围 [&vec[0], &vec[vec.capacity()) 用作正常数组.例如，

With vectors, one can assume that elements are stored contiguously in memory, allowing the range [&vec[0], &vec[vec.capacity()) to be used as a normal array. E.g.,

vector<char> buf;
buf.reserve(N);
int M = read(fd, &buf[0], N);

但现在向量不知道它包含 M 字节的数据，由 read() 从外部添加.我知道 vector::resize() 设置大小，但它也清除数据，所以它不能用于更新 read() 后的大小打电话.

But now the vector doesn't know that it contains M bytes of data, added externally by read(). I know that vector::resize() sets the size, but it also clears the data, so it can't be used to update the size after the read() call.

是否有一种简单的方法可以将数据直接读入向量并在之后更新大小?是的，我知道一些明显的解决方法，例如使用小数组作为临时读取缓冲区，并使用 vector::insert() 将其附加到向量的末尾:

Is there a trivial way to read data directly into vectors and update the size after? Yes, I know of the obvious workarounds like using a small array as a temporary read buffer, and using vector::insert() to append that to the end of the vector:

char tmp[N];
int M = read(fd, tmp, N);
buf.insert(buf.end(), tmp, tmp + M)

这行得通(这就是我今天要做的)，但让我烦恼的是，如果我可以将数据直接放入其中，则不需要额外的复制操作矢量.

This works (and it's what I'm doing today), but it just bothers me that there is an extra copy operation there that would not be required if I could put the data directly into the vector.

那么，在外部添加数据时，有没有一种简单的方法可以修改矢量大小?

So, is there a simple way to modify the vector size when data has been added externally?

推荐答案

vector<char> buf;
buf.reserve(N);
int M = read(fd, &buf[0], N);

此代码片段调用未定义的行为.你不能写超过 size() 元素，即使你已经预留了空间.

This code fragment invokes undefined behavior. You can't write beyond than size() elements, even if you have reserved the space.

正确的代码如下:

vector<char> buf;
buf.resize(N);
int M = read(fd, &buf[0], N);
buf.resize(M);

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PS. 您的陈述对于向量，人们可以假设元素连续存储在内存中，允许范围 [&vec[0], &vec[vec.capacity()) 用作普通数组"是不正确的.允许的范围是[&vec[0], &vec[vec.size()).

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PS. Your statement "With vectors, one can assume that elements are stored contiguously in memory, allowing the range [&vec[0], &vec[vec.capacity()) to be used as a normal array" isn't true. The allowable range is [&vec[0], &vec[vec.size()).

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