如何在布尔值(假和真)上编写“for"循环

How to write a `for` loop over bool values (false and true)(如何在布尔值(假和真)上编写“for循环)

问题描述

一个主要是为了好玩/好奇的问题:如何在 C++ 中编写一个 for 循环，该循环将遍历 bool 的两个值(即 true 和 false)，只使用带有 bool 的操作(即不转换为其他类型)?

A question mostly for fun/curiosity: how to write a for loop in C++ that would iterate over two values of a bool (i.e. true and false), using only operations with bool (i.e. without conversions to other types)?

背景是我想检查像 (A && B) || 这样的方程存在多少解.(!B && !C && !D) == true，并开始写类似 for (bool A=false; ??? ; ++A) for (bool B=false; ...) 等但立即被 ??? 卡住 - 即继续循环的条件是什么?当然我重写了它以使用 int，而且我也知道 do ... while 循环会起作用，但我很好奇是否有可能编写这样的 for 循环?由于SO似乎没有答案，我决定问:)

The background is that I wanted to check how many solutions exists for an equation like (A && B) || (!B && !C && !D) == true, and started to write something like for (bool A=false; ??? ; ++A) for (bool B=false; ...) etc but immediately got stuck by ??? - i.e. what would be the condition to continue the loop? Of course I rewrote it to use int, and I also know that a do ... while loop will work, but I got curious if it's ever possible to write such a for loop? And since SO does not seem to have an answer, I decided to ask :)

更新:请注意，在至少两个现已删除的答案中建议的明显"变体 for(bool A=false; !A; A=true) 只会运行一次迭代，因为对于第二个条件 !A 变为 false 并且循环结束.

Update: note that an "obvious" variant for(bool A=false; !A; A=true) suggested in at least two now-removed answers will only run one iteration, because for the second one the condition !A becomes false and the loop ends.

经过一番思考，我相信如果没有第二个变量或 Dietmar Kühl 建议的基于指针的构造，在 C++03 中是不可能做到的.该条件应在所需的执行中测试 3 次，因此两个布尔值是不够的.而 do-while 循环之所以有效，是因为第一次迭代是无条件执行的，条件只检查了两次，因此可以使用 bool 值在继续和退出之间进行选择.

After some pondering, I believe it's impossible to do it in C++03 without a second variable or a pointer based construct like suggested by Dietmar Kühl. The condition should be tested three times in a desired execution, so two values of a bool are simply not enough. And the do-while loop works because the first iteration is executed unconditionally, the condition is only checked twice and so a bool value can be used to select between continuing and exiting.

推荐答案

在 C++11 中:for (bool b : { false, true }) {/* ... *