yaml-cpp 读取项目中的序列

yaml-cpp read sequence in item(yaml-cpp 读取项目中的序列)

问题描述

如何使用 yaml-cpp 读取此 YAML 文件:

How can I read this YAML file with yaml-cpp:

sensors:
  - id: 5
    hardwareId: 28-000005a32133
    type: 1
  - id: 6
    hardwareId: 28-000005a32132
    type: 4

我不明白如何获得 sensors 项目，以使用它.

I can't understand how can I get sensors item, to use it.

据我了解，sensors 是一个 YAML::Node.我怎样才能得到它?

As I understand sensors is a YAML::Node. How can I get it?

更新 1:

YAML::Node config = YAML::LoadFile(config_path);
const YAML::Node& node_test1 = confg["sensors"];

for (std::size_t i = 0; i < node_test1.size(); i++) {
    const YAML::Node& node_test2 = node_test1[i];
    std::cout << "Id: " << node_test2["id"].as<std::string>() << std::endl;
    std::cout << "hardwareId: " << node_test2["hardwareId"].as<std::string>() << std::endl << std::endl;
}

此代码有效，但它是使用有关旧 api 的教程编写的.我认为这段代码可以用迭代器重写，但我现在不知道如何.

This code works, but it was writed using tutorial about old api. I think this code could be rewrited with iterators, but I don't now how.

推荐答案

看起来你的代码可以工作，但是如果你想用迭代器重写它，你可以:

It looks like your code works, but if you want to rewrite it with iterators, you can:

YAML::Node config = YAML::LoadFile(config_path);
const YAML::Node& sensors = config["sensors"];
for (YAML::iterator it = sensors.begin(); it != sensors.end(); ++it) {
    const YAML::Node& sensor = *it;
    std::cout << "Id: " << sensor["id"].as<std::string>() << "
";
    std::cout << "hardwareId: " << sensor["hardwareId"].as<std::string>() << "

";
}

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