Speedup a short to float cast?(加快浮动转换的速度?)
问题描述
我在 C++ 中的浮点类型转换很短,这对我的代码造成了瓶颈.
I have a short to float cast in C++ that is bottlenecking my code.
代码从一个硬件设备缓冲区转换而来,该缓冲区本身是短路的,这表示来自花哨的光子计数器的输入.
The code translates from a hardware device buffer which is natively shorts, this represents the input from a fancy photon counter.
float factor= 1.0f/value;
for (int i = 0; i < W*H; i++)//25% of time is spent doing this
{
int value = source[i];//ushort -> int
destination[i] = value*factor;//int*float->float
}
一些细节
取值范围为 0 到 2^16-1,代表高灵敏度相机的像素值
Value should go from 0 to 2^16-1, it represents the pixel values of a highly sensitive camera
我在一台配备 i7 处理器(i7 960,即 SSE 4.2 和 4.1)的多核 x86 机器上.
I'm on a multicore x86 machine with an i7 processor (i7 960 which is SSE 4.2 and 4.1).
源与 8 位边界对齐(硬件设备的要求)
Source is aligned to an 8 bit boundary (a requirement of the hardware device)
W*H 总是能被 8 整除,大多数时候 W 和 H 都能被 8 整除
W*H is always divisible by 8, most of the time W and H are divisible by 8
这让我很难过,我能做些什么吗?
This makes me sad, is there anything I can do about it?
我正在使用 Visual Studios 2012...
I am using Visual Studios 2012...
推荐答案
这是一个基本的 SSE4.1 实现:
Here's a basic SSE4.1 implementation:
__m128 factor = _mm_set1_ps(1.0f / value);
for (int i = 0; i < W*H; i += 8)
{
// Load 8 16-bit ushorts.
// vi = {a,b,c,d,e,f,g,h}
__m128i vi = _mm_load_si128((const __m128i*)(source + i));
// Convert to 32-bit integers
// vi0 = {a,0,b,0,c,0,d,0}
// vi1 = {e,0,f,0,g,0,h,0}
__m128i vi0 = _mm_cvtepu16_epi32(vi);
__m128i vi1 = _mm_cvtepu16_epi32(_mm_unpackhi_epi64(vi,vi));
// Convert to float
__m128 vf0 = _mm_cvtepi32_ps(vi0);
__m128 vf1 = _mm_cvtepi32_ps(vi1);
// Multiply
vf0 = _mm_mul_ps(vf0,factor);
vf1 = _mm_mul_ps(vf1,factor);
// Store
_mm_store_ps(destination + i + 0,vf0);
_mm_store_ps(destination + i + 4,vf1);
}
假设:
source
和destination
都对齐到 16 个字节.W*H
是 8 的倍数.
source
anddestination
are both aligned to 16 bytes.W*H
is a multiple of 8.
进一步展开此循环可能会做得更好.(见下文)
It's possible to do better by further unrolling this loop. (see below)
这里的思路如下:
- 将 8 个短路加载到单个 SSE 寄存器中.
- 将收银机分成两部分:一个是底部 4 条短裤,另一个是顶部 4 条短裤.
- 将两个寄存器零扩展为 32 位整数.
- 将它们都转换为
float
s. - 乘以系数.
- 将它们存储到
destination
.
<小时>
我已经有一段时间没有做这种优化了,所以我继续展开循环.
It's been a while since I've done this type of optimization, so I went ahead and unrolled the loops.
Core i7 920 @ 3.5 GHz
Visual Studio 2012 - 发布 x64:
Original Loop : 4.374 seconds
Vectorize no unroll: 1.665
Vectorize unroll 2 : 1.416
进一步展开导致收益递减.
Further unrolling resulted in diminishing returns.
这是测试代码:
#include <smmintrin.h>
#include <time.h>
#include <iostream>
#include <malloc.h>
using namespace std;
void default_loop(float *destination,const short* source,float value,int size){
float factor = 1.0f / value;
for (int i = 0; i < size; i++)
{
int value = source[i];
destination[i] = value*factor;
}
}
void vectorize8_unroll1(float *destination,const short* source,float value,int size){
__m128 factor = _mm_set1_ps(1.0f / value);
for (int i = 0; i < size; i += 8)
{
// Load 8 16-bit ushorts.
__m128i vi = _mm_load_si128((const __m128i*)(source + i));
// Convert to 32-bit integers
__m128i vi0 = _mm_cvtepu16_epi32(vi);
__m128i vi1 = _mm_cvtepu16_epi32(_mm_unpackhi_epi64(vi,vi));
// Convert to float
__m128 vf0 = _mm_cvtepi32_ps(vi0);
__m128 vf1 = _mm_cvtepi32_ps(vi1);
// Multiply
vf0 = _mm_mul_ps(vf0,factor);
vf1 = _mm_mul_ps(vf1,factor);
// Store
_mm_store_ps(destination + i + 0,vf0);
_mm_store_ps(destination + i + 4,vf1);
}
}
void vectorize8_unroll2(float *destination,const short* source,float value,int size){
__m128 factor = _mm_set1_ps(1.0f / value);
for (int i = 0; i < size; i += 16)
{
__m128i a0 = _mm_load_si128((const __m128i*)(source + i + 0));
__m128i a1 = _mm_load_si128((const __m128i*)(source + i + 8));
// Split into two registers
__m128i b0 = _mm_unpackhi_epi64(a0,a0);
__m128i b1 = _mm_unpackhi_epi64(a1,a1);
// Convert to 32-bit integers
a0 = _mm_cvtepu16_epi32(a0);
b0 = _mm_cvtepu16_epi32(b0);
a1 = _mm_cvtepu16_epi32(a1);
b1 = _mm_cvtepu16_epi32(b1);
// Convert to float
__m128 c0 = _mm_cvtepi32_ps(a0);
__m128 d0 = _mm_cvtepi32_ps(b0);
__m128 c1 = _mm_cvtepi32_ps(a1);
__m128 d1 = _mm_cvtepi32_ps(b1);
// Multiply
c0 = _mm_mul_ps(c0,factor);
d0 = _mm_mul_ps(d0,factor);
c1 = _mm_mul_ps(c1,factor);
d1 = _mm_mul_ps(d1,factor);
// Store
_mm_store_ps(destination + i + 0,c0);
_mm_store_ps(destination + i + 4,d0);
_mm_store_ps(destination + i + 8,c1);
_mm_store_ps(destination + i + 12,d1);
}
}
void print_sum(const float *destination,int size){
float sum = 0;
for (int i = 0; i < size; i++){
sum += destination[i];
}
cout << sum << endl;
}
int main(){
int size = 8000;
short *source = (short*)_mm_malloc(size * sizeof(short), 16);
float *destination = (float*)_mm_malloc(size * sizeof(float), 16);
for (int i = 0; i < size; i++){
source[i] = i;
}
float value = 1.1;
int iterations = 1000000;
clock_t start;
// Default Loop
start = clock();
for (int it = 0; it < iterations; it++){
default_loop(destination,source,value,size);
}
cout << (double)(clock() - start) / CLOCKS_PER_SEC << endl;
print_sum(destination,size);
// Vectorize 8, no unroll
start = clock();
for (int it = 0; it < iterations; it++){
vectorize8_unroll1(destination,source,value,size);
}
cout << (double)(clock() - start) / CLOCKS_PER_SEC << endl;
print_sum(destination,size);
// Vectorize 8, unroll 2
start = clock();
for (int it = 0; it < iterations; it++){
vectorize8_unroll2(destination,source,value,size);
}
cout << (double)(clock() - start) / CLOCKS_PER_SEC << endl;
print_sum(destination,size);
_mm_free(source);
_mm_free(destination);
system("pause");
}
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本文标题为:加快浮动转换的速度?
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