Base class pointer vs inherited class pointer?(基类指针与继承类指针?)
问题描述
Suppose I have a class Dog
that inherits from a class Animal
. What is the difference between these two lines of code?
Animal *a = new Dog();
Dog *d = new Dog();
In one, the pointer is for the base class, and in the other, the pointer is for the derived class. But when would this distinction become important? For polymorphism, either one would work exactly the same, right?
For all purposes of type-checking, the compiler treats a
as if it could point to any Animal, even though you know it points to a Dog:
- You can't pass
a
to a function expecting aDog*
. - You can't do
a->fetchStick()
, wherefetchStick
is a member function ofDog
but notAnimal
. Dog *d2 = dynamic_cast<Dog*>(d)
is probably just a pointer copy on your compiler.Dog *d3 = dynamic_cast<Dog*>(a)
probably isn't (I'm speculating here, I'm not going to bother checking on any compiler. The point is: the compiler likely makes different assumptions abouta
andd
when transforming code).- etc.
You can call virtual functions (that is, the defined polymorphic interface) of Animal equally through either of them, with the same effect. Assuming Dog
hasn't hidden them, anyway (good point, JaredPar).
For non-virtual functions which are defined in Animal, and also defined (overloaded) in Dog, calling that function via a
is different from calling it via d
.
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