Find extreme outer points in image with Python OpenCV(使用 Python OpenCV 查找图像中的极端外部点)
问题描述
我有这个雕像的图像.
我正在尝试找到雕像的顶部、底部、左侧和最右侧的点.有没有办法测量每边的边缘以确定雕像上的最外点?我想得到每一边的 (x,y)
坐标.我尝试使用 cv2.findContours()
和 cv2.drawContours()
来获得雕像的轮廓.
导入 cv2img = cv2.imread('statue.png')灰色 = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)轮廓 = cv2.findContours(灰色,cv2.RETR_TREE,cv2.CHAIN_APPROX_SIMPLE)[0]cv2.drawContours(img, 轮廓, -1, (0, 200, 0), 3)cv2.imshow('img', img)cv2.waitKey()
这是一个潜在的方法:
将图像转换为 或
argmax()
像这样确定外左、右、上、下坐标left = tuple(c[c[:, :, 0].argmin()][0])对 = 元组(c[c[:, :, 0].argmax()][0])top = tuple(c[c[:, :, 1].argmin()][0])底部 = 元组(c[c[:, :, 1].argmax()][0])
这是结果
<块引用>左:(162, 527)
<块引用>
右:(463, 467)
<块引用>
顶部:(250, 8)
<块引用>
底部:(381, 580)
导入 cv2将 numpy 导入为 np# 加载图像,灰度,高斯模糊,阈值图像 = cv2.imread('1.png')灰色 = cv2.cvtColor(图像,cv2.COLOR_BGR2GRAY)模糊 = cv2.GaussianBlur(灰色, (3,3), 0)thresh = cv2.threshold(模糊, 220, 255, cv2.THRESH_BINARY_INV)[1]# 寻找轮廓cnts = cv2.findContours(thresh, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)cnts = cnts[0] 如果 len(cnts) == 2 否则 cnts[1]c = max(cnts, key=cv2.contourArea)# 获取外坐标left = tuple(c[c[:, :, 0].argmin()][0])对 = 元组(c[c[:, :, 0].argmax()][0])top = tuple(c[c[:, :, 1].argmin()][0])底部 = 元组(c[c[:, :, 1].argmax()][0])# 在图像上画点cv2.drawContours(图像, [c], -1, (36, 255, 12), 2)cv2.circle(图像, 左, 8, (0, 50, 255), -1)cv2.circle(图像, 右, 8, (0, 255, 255), -1)cv2.circle(图像, 顶部, 8, (255, 50, 0), -1)cv2.circle(图像, 底部, 8, (255, 255, 0), -1)print('left: {}'.format(left))print('right: {}'.format(right))print('top: {}'.format(top))print('bottom: {}'.format(bottom))cv2.imshow('thresh', thresh)cv2.imshow('图像', 图像)cv2.waitKey()
I have this image of a statue.
I'm trying to find the top, bottom, left, and right most points on the statue. Is there a way to measure the edge of each side to determine the outer most point on the statue? I want to get the
(x,y)
coordinate of each side. I have tried to usecv2.findContours()
andcv2.drawContours()
to get an outline of the statue.import cv2 img = cv2.imread('statue.png') gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY) contours = cv2.findContours(gray, cv2.RETR_TREE, cv2.CHAIN_APPROX_SIMPLE)[0] cv2.drawContours(img, contours, -1, (0, 200, 0), 3) cv2.imshow('img', img) cv2.waitKey()
解决方案Here's a potential approach:
Convert image to grayscale and Gaussian blur
Threshold to obtain a binary image
Find contours
Obtain outer coordinates
After converting to grayscale and blurring image, we threshold to get a binary image
Now we find contours using
cv2.findContours()
. Since OpenCV uses Numpy arrays to encode images, a contour is simply a Numpy array of(x,y)
coordinates. We can slice the Numpy array and useargmin()
orargmax()
to determine the outer left, right, top, and bottom coordinates like thisleft = tuple(c[c[:, :, 0].argmin()][0]) right = tuple(c[c[:, :, 0].argmax()][0]) top = tuple(c[c[:, :, 1].argmin()][0]) bottom = tuple(c[c[:, :, 1].argmax()][0])
Here's the result
left: (162, 527)
right: (463, 467)
top: (250, 8)
bottom: (381, 580)
import cv2 import numpy as np # Load image, grayscale, Gaussian blur, threshold image = cv2.imread('1.png') gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY) blur = cv2.GaussianBlur(gray, (3,3), 0) thresh = cv2.threshold(blur, 220, 255, cv2.THRESH_BINARY_INV)[1] # Find contours cnts = cv2.findContours(thresh, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE) cnts = cnts[0] if len(cnts) == 2 else cnts[1] c = max(cnts, key=cv2.contourArea) # Obtain outer coordinates left = tuple(c[c[:, :, 0].argmin()][0]) right = tuple(c[c[:, :, 0].argmax()][0]) top = tuple(c[c[:, :, 1].argmin()][0]) bottom = tuple(c[c[:, :, 1].argmax()][0]) # Draw dots onto image cv2.drawContours(image, [c], -1, (36, 255, 12), 2) cv2.circle(image, left, 8, (0, 50, 255), -1) cv2.circle(image, right, 8, (0, 255, 255), -1) cv2.circle(image, top, 8, (255, 50, 0), -1) cv2.circle(image, bottom, 8, (255, 255, 0), -1) print('left: {}'.format(left)) print('right: {}'.format(right)) print('top: {}'.format(top)) print('bottom: {}'.format(bottom)) cv2.imshow('thresh', thresh) cv2.imshow('image', image) cv2.waitKey()
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本文标题为:使用 Python OpenCV 查找图像中的极端外部点
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