How to terminate a thread in Python?(如何在Python中终止线程?)
本文介绍了如何在Python中终止线程?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我知道这个主题已经讨论过几次了,不管我怎么尝试,或者至少尝试了几乎所有的解决方案,但是作为一个相当新的python创建器,我之前的任何解决方案都无法运行。
脚本的基本前提是订阅MQTT Broker并等待命令,单个动作命令100%工作,但是其中一个命令需要循环无限期运行,直到收到另一个命令,因此最合适的解决方案是在单独的线程中运行"循环",同时主订户循环继续"监听"下一个命令。
一切正常(95%),"静电"命令通过并且任务运行良好,那么当"mtg"命令通过它时,它将操作线程,循环运行100%,但是,当收到下一个命令时,我可以确认"if"语句在将消息打印到控制台时处理该命令,但是thread.stop()没有运行,或者它可能正在运行,但它不会终止线程--我正在竭尽全力试图弄清楚这一点。
部分代码:
from sys import exit
import blinkt
import threading
import time
MQTT_SERVER = '192.168.x.x'
MQTT_PORT = 1883
MQTT_TOPIC = 'mytopic'
REDS = [0, 0, 0, 0, 0, 16, 64, 255, 64, 16, 0, 0, 0, 0, 0, 0]
start_time = time.time()
class task(threading.Thread):
def __init__(self):
threading.Thread.__init__(self)
self.kill = threading.Event()
self.event = threading.Event()
self._stop = threading.Event()
def run(self):
# while not self.kill.is_set():
while True:
if self.stopped():
return
self.start_run()
def stop(self):
# self.event.set()
self._stop.set()
def stopped(self):
return self._stop.isSet()
def start_run(self):
# while True: <-- no longer needed as the run method loops the process.
delta = (time.time() - start_time) * 16
offset = int(abs((delta % len(REDS)) - blinkt.NUM_PIXELS))
for i in range(blinkt.NUM_PIXELS):
blinkt.set_pixel(i, REDS[offset + i], 0, 0)
blinkt.show()
time.sleep(0.1)
def on_connect(client, userdata, flags, rc):
print('Connected with result code ' + str(rc))
client.subscribe(MQTT_TOPIC)
def on_message(client, userdata, msg):
data = msg.payload
if type(data) is bytes:
data = data.decode('utf-8')
data = data.split(',')
command = data.pop(0)
if command == 'clr' and len(data) == 0:
blinkt.clear()
blinkt.show()
t1.stop() #<--- I've tried a few ways to get the task to stop when the "clr" command is recieved
task.stop()
return
if command == 'rgb' and len(data) == 4: #<-- This code block works fine, msg arrives and LEDs are set correctly
try:
pixel = data.pop(0)
if pixel == '*':
pixel = None
else:
pixel = int(pixel)
if pixel > 7:
print('Pixel out of range: ' + str(pixel))
return
r, g, b = [int(x) & 0xff for x in data]
print(command, pixel, r, g, b)
except ValueError:
print('Malformed command: ' + str(msg.payload))
return
if pixel is None:
for x in range(blinkt.NUM_PIXELS):
blinkt.set_pixel(x, r, g, b)
else:
blinkt.set_pixel(pixel, r, g, b)
blinkt.show()
return
if command == 'mtg' and len(data) == 0:
print(command)
t1 = task()
t1.start() #<-- Here is where the Thread is called to start and seems to run ok
return
blinkt.set_clear_on_exit()
client = mqtt.Client()
client.on_connect = on_connect
client.on_message = on_message
client.connect(MQTT_SERVER, MQTT_PORT, 60)
client.loop_forever()
推荐答案
您的t1
变量是本地变量,因此当您退出on_message
函数时它会丢失。此外,您正在合并类task
和实例t1
(task.stop()
将不起作用)。
为快速解决问题,请将t1 = None
声明为全局变量,然后将global t1
添加到on_message
函数.
但是,我会考虑重构,这样就有一个始终运行的线程来命令Blinkt!,而MQTT消息处理程序只需相应地设置其状态-就像这样。显然是干编的,所以可能有些愚蠢。
from sys import exit
import blinkt
import threading
import time
MQTT_SERVER = "192.168.x.x"
MQTT_PORT = 1883
MQTT_TOPIC = "mytopic"
REDS = [0, 0, 0, 0, 0, 16, 64, 255, 64, 16, 0, 0, 0, 0, 0, 0]
start_time = time.time()
class BlinktManager(threading.Thread):
def __init__(self):
threading.Thread.__init__(self)
self.stop_event = threading.Event()
self.mode = None
def run(self):
while not self.stop_event.isSet():
self.tick()
self.stop_event.wait(0.1) # instead of sleep
def tick(self):
if self.mode == "reds":
self._tick_reds()
def _tick_reds(self):
delta = (time.time() - start_time) * 16
offset = int(
abs((delta % len(REDS)) - blinkt.NUM_PIXELS)
)
for i in range(blinkt.NUM_PIXELS):
blinkt.set_pixel(i, REDS[offset + i], 0, 0)
blinkt.show()
def clear(self):
self.mode = None
blinkt.clear()
blinkt.show()
def set_all_pixels(self, r, g, b):
self.mode = None
for x in range(blinkt.NUM_PIXELS):
blinkt.set_pixel(x, r, g, b)
blinkt.show()
def set_pixel(self, x, r, g, b):
self.mode = None
blinkt.set_pixel(x, r, g, b)
blinkt.show()
def begin_reds(self):
self.mode = "reds"
def on_connect(client, userdata, flags, rc):
print("Connected with result code " + str(rc))
client.subscribe(MQTT_TOPIC)
def on_message(client, userdata, msg):
data = msg.payload
if type(data) is bytes:
data = data.decode("utf-8")
data = data.split(",")
command = data.pop(0)
if command == "clr" and len(data) == 0:
blinkt_manager.clear()
if command == "rgb" and len(data) == 4:
x = data[0]
r, g, b = [int(x) & 0xFF for x in data[1:]]
if x == "*":
blinkt_manager.set_all_pixels(r, g, b)
else:
# TODO: error handling
blinkt_manager.set_pixel(int(x), r, g, b)
if command == "mtg" and len(data) == 0:
blinkt_manager.begin_reds()
blinkt.set_clear_on_exit()
blinkt_manager = BlinktManager()
blinkt_manager.start()
client = mqtt.Client()
client.on_connect = on_connect
client.on_message = on_message
client.connect(MQTT_SERVER, MQTT_PORT, 60)
client.loop_forever()
这篇关于如何在Python中终止线程?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
沃梦达教程
本文标题为:如何在Python中终止线程?
基础教程推荐
猜你喜欢
- 使用Python匹配Stata加权xtil命令的确定方法? 2022-01-01
- 如何在 Python 中检测文件是否为二进制(非文本)文 2022-01-01
- 症状类型错误:无法确定关系的真值 2022-01-01
- 使用 Google App Engine (Python) 将文件上传到 Google Cloud Storage 2022-01-01
- Python 的 List 是如何实现的? 2022-01-01
- 将 YAML 文件转换为 python dict 2022-01-01
- 合并具有多索引的两个数据帧 2022-01-01
- 使 Python 脚本在 Windows 上运行而不指定“.py";延期 2022-01-01
- 如何在Python中绘制多元函数? 2022-01-01
- 哪些 Python 包提供独立的事件系统? 2022-01-01