在泡菜文件中保存和加载多个对象?

Saving and loading multiple objects in pickle file?(在泡菜文件中保存和加载多个对象?)

问题描述

我有一个类为游戏中的玩家服务，创建他们和其他东西.

I have a class that serves players in a game, creates them and other things.

我需要将这些播放器对象保存在一个文件中以供以后使用.我已经尝试过 pickle 模块，但我不知道如何保存多个对象并再次加载它们?有没有办法做到这一点，或者我应该使用其他类(如列表)并将我的对象保存和加载到列表中?

I need to save these player objects in a file to use it later. I've tried the pickle module but I don't know how to save multiple objects and again loading them? Is there a way to do that or should I use other classes such as lists and save and load my objects in a list?

有没有更好的办法?

推荐答案

使用列表、元组或字典是迄今为止最常见的方法:

Using a list, tuple, or dict is by far the most common way to do this:

import pickle
PIK = "pickle.dat"

data = ["A", "b", "C", "d"]
with open(PIK, "wb") as f:
    pickle.dump(data, f)
with open(PIK, "rb") as f:
    print pickle.load(f)

打印出来的:

['A', 'b', 'C', 'd']

然而，一个泡菜文件可以包含任意数量的泡菜.这是产生相同输出的代码.但请注意，它更难编写和理解:

However, a pickle file can contain any number of pickles. Here's code producing the same output. But note that it's harder to write and to understand:

with open(PIK, "wb") as f:
    pickle.dump(len(data), f)
    for value in data:
        pickle.dump(value, f)
data2 = []
with open(PIK, "rb") as f:
    for _ in range(pickle.load(f)):
        data2.append(pickle.load(f))
print data2

如果你这样做，你有责任知道你写出的文件中有多少泡菜.上面的代码通过首先挑选列表对象的数量来做到这一点.

If you do this, you're responsible for knowing how many pickles are in the file you write out. The code above does that by pickling the number of list objects first.

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